Answer:
The cost of 2 quintal of rice is $10,000.
Step-by-step explanation:
To determine the cost of 2 quintals of rice, knowing that 90 kilos of said product is worth $ 4,500, it is first necessary to establish the equivalence between quintals and kilograms. In this regard, a quintal is equivalent to 100 kilograms, so 2 quintals are equivalent to 200 kilos.
Now, to determine the cost per kilogram of rice, the following calculation is required:
4,500 / 90 = X
50 = X
Therefore, 1 kilogram of rice costs $ 50. Thus, since 200 x 50 equals 10,000, 2 quintals of rice will cost $ 10,000.
A) y-axis
B) quad lll
C) x-axis
D) quad IV
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Answer:
f(x) = -2x² - 8x - 2
General Formulas and Concepts:
- Order of Operations: BPEMDAS
- Expand by FOIL (First Outside Inside Last)
- Standard Form: f(x) = ax² + bx + c
- Vertex Form: f(x) = a(bx + c)² + d
Step-by-step explanation:
<u>Step 1: Define function</u>
Vertex Form: f(x) = -2(x + 2)² + 6
<u>Step 2: Find Standard Form</u>
- Expand by FOILing: f(x) = -2(x² + 4x + 4) + 6
- Distribute -2: f(x) = -2x² - 8x - 8 + 6
- Combine like terms (constants): f(x) = -2x² - 8x - 2
Answer:
67,500 m²
Step-by-step explanation:
ASSUMING the fields look like this __________________
| | |
| | | W
|_________|_________|
L
Let L be the length of the combined field and W be the width
2L + 3W = 1800
2L = 1800 - 3W
L = 900 - 1.5W
A = LW
A = (900 - 1.5W)W
A = 900W - 1.5W²
Area will be maximized when the derivative equals zero.
dA/dW = 900 - 3W
0 = 900 - 3W
3W = 900
W = 300 m
L = 900 - 1.5(300)
L = 450 m
A = LW = 450(300) = 135,000 m²
so each sub field is 135000/2 = 67,500 m²
