First let us find


Now let;s solve the second part
Answer:
49°
Step-by-step explanation:
7.5x-15+90=180
7.5x+75 =180
7.5x=105
x =14
so NPQ = ( 4×14 -7 ) = 49° this the answer
Answer:
min-mid-max-mid-min
-cosine
Step-by-step explanation:
This is the correct answer, further proof in the file attached.
Answer:
7.07 units
Step-by-step explanation:
Use the Pythagorean theorem for the right triangle:

If a = x, b = x, and c = 10, then

Answer: 764
Step-by-step explanation: