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natima [27]
3 years ago
6

Who is captain america​

Business
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

a super hero that's part of marvel

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Which of the following LEAST describes the concept of brand equity? Select one:
Julli [10]

Answer:

The statement states least regarding the brand equity concept is option A

Explanation:

Brand equity is the value or value premium which a firm generates  or create for the product with a name that is recognizable when compared to the generic equivalent. It is used by companies for creating a brand for their products by making them superior in reliability and quality.

So, the one which state least regarding the same that it provide information for assessing the maximizing of the supply chain.

6 0
3 years ago
Melanie invests $4,000 into an account offering 4% interest compounded annually. Gina invests $4,000 into a simple interest savi
denpristay [2]

Answer:

$4,900 (From simple interest method)

Explanation:

Given:

Amount invested (p) = $4,000

Interest rate for simple interest (r) = 4.5% = 4.5/100 = 0.045

Interest rate for Compound interest (i) = 4%

Number of year (t) = 5

Computation of amount from simple interest method:

Amount = p(1+rt)

Amount = $4,000[1+(0.045 × 5)]

Amount = $4,000[1+0.225]

Amount = $4,000[1.225]

Amount (from simple interest method) = $4,900

Computation of amount from compound interest method:

Amount = p(1+i)^t\\\\Amount = 4,000(1+0.04)^5\\\\Amount = 4,000(1.04)^5\\\\Amount = 4,000(1.2166529)\\\\Amount = 4,866.616\\\\

Therefore, Amount from simple interest method is higher .

3 0
3 years ago
You decide to go on a shopping spree. You make a purchase at Sears, and the cashiers says "Can I put your purchase on your Sears
bagirrra123 [75]

Answer:

B i think

Explanation:

4 0
3 years ago
When interest is compounded continuously, the amount of money increases at a rate proportional to the amount S present at time t
liubo4ka [24]

Answer:

a) - r=5%: S=$ 5,136.10

- r=4%: S=$ 4,885.61

- r=3%: S=$ 4,647.34

b) - r=5%: t=14 years

- r=4%: t=17 years  [/tex]

- r=3%: t=23 years  [/tex]

c) The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

Explanation:

The rate of accumulation of money is

dS/dt=rS

To calculate the amount of money accumulted in a period, we have to rearrange and integrate:

\int dS/S=\int rdt=r \int dt\\\\ln(S)=C*r*t\\\\S=C*e^{rt}

When t=0, S=S₀ (the initial capital).

S=S_0=Ce^{r*0}=Ce^0=C\\\\C=S_0

Now we have the equation for the capital in function of time:

S=S_0e^{rt}

a) For an initial capital of $4000 and for a period of five years, the amount of capital accumulated for this interest rates is:

- r=5%: S=4000e^{0.05*5}=4000*e^{0.25}= 5,136.10

- r=4%: S=4000e^{0.04*5}=4000*e^{0.20}=  4,885.61

- r=3%: S=4000e^{0.03*5}=4000*e^{0.15}=   4,647.34

b) We can express this as

S=S_0e^{rt}\\\\2S_0=S_0e^{rt}\\\\2=e^{rt}\\\\ln(2)=rt\\\\t=ln(2)/r

- r=5%: t=ln(2)/0.05=14

- r=4%: t=ln(2)/0.04=17

- r=3%: t=ln(2)/0.03=  23

c) When the interest is compuonded quarterly, the anual period is divided by 4. In 5 years, there are 4*5=20 periods of capitalization. The annual rate r=0.0525 to calculate the interest is also divided by 4:

S = 4000 (1+(1/4)(0.0525))^{5*4}=4000(1.013125)^{20}\\\\S=4000*1.297958= 5,191.83

If compuonded continously, we have:

S=S_0e^{rt}=4000*e^{0.0525*5}=4000*1.3= 5,200.71

The amount obtained is

- Compuonded quarterly: $5,191.83

- Compuonded continously: $5,200.71

The latter is always greater, since the more often it is capitalized, the greater the effect of compound interest and the greater the capital that ends up accumulating.

5 0
3 years ago
On January​ 2, 2019, Kornis Corporation acquired equipment for $ 1 comma 000 comma 000. The estimated life of the equipment is 5
Nat2105 [25]

Answer:

Depreciation by December 31, 2019=$400,000

Explanation:

The expression for the accumulated depreciation is as follows;

accumulated depreciation=Acquisition cost-residual value

where;

acquisition cost=$1,000,000

residual value=$40,000

replacing;

depreciable cost=1,000,000-40,000=$960,000

depreciable cost=$960,000

The annual depreciation can be expressed as;

annual depreciation=depreciable cost/estimated life

where;

depreciable cost=$960,000

estimated life=5 years

replacing;

annual depreciation=960,000/5=192,000

annual depreciation=$192,000

depreciation rate=annual depreciation/depreciable cost×100

depreciable rate=(192,000/960,000)×100=20%

Since it is a double-declining depreciation rate we multiple the depreciable rate by 2;

(20%×2)=40%

Depreciation by December=carrying value×rate

Depreciation by December 31, 2019=1,000,000×40%=$400,000

4 0
3 years ago
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