Answer:
Grams of the reactant would be required is 8.26 g
Explanation:
Decomposition of NI3 is :
2 NI3 (s) --------------------> N2 (g)............... +..................... 3 I2 (g)
2 mol..................................1 mol.........................................3 mol
2 x 394.7 g/mol..............28 g/mol....................................3 x 253.8 g/mol
789.4 g...............................28 g...........................................761.4 g
From chemical equation it is cleared that
761.4 g of iodine is obtained from = 789.4 g of NI3
Therefore,
7.97 g of iodine is obtained from = 789.4 g x 7.97 g / 761.4 of NI3
= 6291.518 / 761.4 of NI3
= 8.26 g of NI3
Hence
Grams of the reactant would be required = 8.26 g
Answer:
<h2>
<u>OH-</u> es el símbolo del agua ozonizada.</h2>
Answer:
2KClO3 —> 2KCl + 3O2
The coefficients are 2, 2, 3
Explanation:
From the question given above, we obtained the following equation:
KClO3 —> 2KCl + 3O2
The above equation can be balance as follow:
There are 2 atoms of K on the right side and 1 atom on the left side. It can be balance by putting 2 in front of KClO3 as shown below:
2KClO3 —> 2KCl + 3O2
Now, the equation is balanced.
Thus, the coefficients are 2, 2, 3
Add proton + neutrons = Mass 37
Proton is same as your atomic mass= 17
If you go on the periodic table look up 17 and it will give u the letter.
