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omeli [17]
3 years ago
14

9. Mary is running at a pace where it takes him 8 minutes to run one mile. Let T represent the time that Mary has run, in minute

s, and let D represent the distance he has run, in miles.
​
Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer:

rate that Mary has run:  D = 8T

Step-by-step explanation:

distance = rate × time

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What is the exact value of x in the exponential equation 22.1 + e5x = 100.1?
sergij07 [2.7K]
I think the answer is 15.6

5 0
3 years ago
Use the table to work out the values of a , b , c , and d .​
rodikova [14]

Answer:

a = 16, b = 6, c = - 4, d = - 9

Step-by-step explanation:

Substitute the appropriate values of x into the equation and evaluate.

x = - 3 : y = 1 - 5(- 3) = 1 + 15 = 16 → a

x = - 1 : y = 1 - 5(- 1) = 1 + 5 = 6 → b

x = 1 : y = 1 - 5(1) = 1 - 5 = - 4 → c

x = 2 : y = 1 - 5(2) = 1 - 10 = - 9 → d

8 0
2 years ago
Read 2 more answers
Jenny just went shoe shopping. Now she has 5 more pairs of shoes than her brother does. Together, they have 25 pairs of shoes.
Assoli18 [71]

Answer:

jenny got 15 pair of shoes

her bro got 10 pairs of shoes

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
-2x – 4 &lt; 3x + 21<br> Solve the inequality
I am Lyosha [343]

Isolate the x. Subtract 3x from both sides, and add 4 to both sides

-2x (-3x) - 4 (+4) < 3x (-3x) + 21 (+4)

-2x - 3x < 21 + 4

Simplify. Combine like terms

-5x < 25

Isolate the x. Divide -5 from both sides (remember to flip the sign).

-5x/-5 < 25/-5

x > 25/-5

x > -5

x > -5 is your answer

hope this helps

7 0
3 years ago
1. Flight 202's arrival time is normally distributed with a mean arrival time of 4:30
Bezzdna [24]

Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

By comparing P(0 ≤ Z ≤ 30)

P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)

Using Table

P(0 ≤ Z ≤ 1) = 0.3413

P(Z > 1) = (0.5 - 0.3413) = 0.1537

∴ P(Z > 45) = 0.1537

2)  By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

P(Z < 1) = (0.5 - 0.3413) = 0.1587

∴ P(Z < 15) = 0.1587

3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)

P(Z ≤ 60 - 30/15) = P(Z ≤ 2)

Using Table

P(0 ≤ Z ≤ 1) = 0.4772

P(Z > 1) = (0.5 - 0.4772) = 0.0228

∴ P(Z > 60) = 0.0228

6 0
3 years ago
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