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otez555 [7]
3 years ago
13

Help asap PLEASE I will give u max everything all that steps if possible

Physics
1 answer:
DiKsa [7]3 years ago
6 0

Explanation:

2. R_T = R_1 + R_2 + R_3 = 625\:Ω + 330\:Ω + 1500\:Ω

\:\:\:\:\:\:\:= 2455\:Ω = 2.455\:kΩ

3. Resistors in series only need to be added together so

R_T = 8(140\:Ω) = 1120\:Ω = 1.12\:kΩ

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A ball of mass 0.120 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.820 m. W
Vikentia [17]

Answer:

1.0752 kgm/s

Explanation:

Considering when the drop was dropped from rest from a height,

mass of the ball, m = 0.120 kg

height, h = - 1.25 m

the initial velocity, u = 0 m/s

the acceleration due to gravity, g = - 9.8 m/s²

From equation of motion

                            V^{2} = U^{2} + 2gh

Substituting the values,

                             V^{2} = 0^{2} + 2(-9.8 m/s^{2})(-1.25 m)

                             V^{2} = 24.5 m/s

                             V = \sqrt{24.5} \ m/s

                             V = 4.95 \ m/s

                            V = ± 4.95 m/s

                            V = - 4.95 m/s

Since the ball is moving downward, the final velocity of the ball when it hits the floor is  V = - 4.95 m/s  

Considering when the ball rebounds from the floor,

assume the mass of the ball still remain, m = 0.120 kg

height, h = 0.820 m

the final velocity, v = 0 m/s  

the acceleration due to gravity, g = - 9.8 m/s²

From equation of motion

                            V^{2} = U^{2} + 2gh

Substituting the values,

                            0^{2} = U^{2} + 2(-9.8 m/s^{2})(0.820 m)

                            0 = U^{2} - 16.072 m/s

                            U^{2} = 16.072 m/s

                            U = \sqrt{16.072} \ m/s

                           U = ± 4.01 m/s

                          U = + 4.01 m/s

Since the ball is moving upward, the initial velocity of the ball from the bounce from the floor is  U = + 4.01 m/s                        

From Newton's second law of motion, applied force is directly proportional to the rate of change in momentum.

                            F = \frac{mv - mu}{t}

                          F.t = m(v - u)

       ⇒      Impulse = Change in momentum

To calculate the impulse, the moment before the ball hits the ground will be the initial momentum while the moment the ball rebounces will be the final velocity,                        

          ∴          F.t = 0.120  kg(4.01  m/s - (-4.95  m/s) )

                      F.t = 0.120  kg(4.01  m/s + 4.95  m/s) )

                      F.t = 0.120  kg × 8.96  m/s

                      Impulse  = 1.0752 kgm/s

The impulse given to the ball by the floor is 1.0752 kgm/s

                             

6 0
3 years ago
If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate
Ulleksa [173]
<span>s= 0.5 at^2
</span>
0.5 x 9.81 x 3^2 = 44m
8 0
3 years ago
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How do you find the angle (to the nearest tenth) on your graph that produced the greatest range, based on the line of best fit?
VikaD [51]

Answer:

yuououiy

Explanation:

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A motorcycle moving at a constant velcoity suddenly accelerates at a rate of 4.0 m/s/s to a speed of 35 m/s in 5.0 s. What was t
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Answer:

15 m/s

Explanation:

v = u+ at

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Which of the following is the method by which air is cooled in the food storage component of a refrigerator?
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