Answer:
for your next answer it will be
Explanation:
2⁶(-4)
All you need to do is count the number of Oxygen the Products:
In 6H2O, you have 6 oxygen, and in 6CO2, you have 6 Dioxygen so 12 Oxygen. So a total of 12 + 6 = 18 atoms of Oxygen, or 9 atoms of dioxygen.
So the coefficient that should be placed in front of O2 to balance the reaction is 9:
C6H12 + 9O2 ---> 6H2O + 6CO2
Hope this Helps! :)
Clever problem.
We know that the beat frequency is the DIFFERENCE between the frequencies of the two tuning forks. So if Fork-A is 256 Hz and the beat is 6 Hz, then Fork-B has to be EITHER 250 Hz OR 262 Hz. But which one is it ?
Well, loading Fork-B with wax increases its mass and makes it vibrate SLOWER, and when that happens, the beat drops to 5 Hz. That means that when Fork-B slowed down, its frequency got CLOSER to the frequency of Fork-A ... their DIFFERENCE dropped from 6 Hz to 5 Hz.
If slowing down Fork-B pushed it CLOSER to the frequency of Fork-A, then its natural frequency must be ABOVE Fork-A.
The natural frequency of Fork-B, after it gets cleaned up and returns to its normal condition, is 262 Hz. While it was loaded with wax, it was 261 Hz.
Answer:
(a) 21.44 ft/s
(b) 0 ft/s
(c) 19.51 ft/s
Explanation:
2 in = 2/12 ft = 0.167 ft
For steady laminar flow, the function of the fluid velocity in term of distance from center is modeled as the following equation:
where R = 0.167 ft is the pipe radius and is the constant fluid velocity at the center of the pipe.
We can integrate this over the cross-section area of the in order to find the volume flow
So the average velocity
b) At the wall of the pipe, r = R so
c) At a distance of 0.6 in = 0.6/12 = 0.05 ft