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Yakvenalex [24]
3 years ago
14

How many centimeters are in 3.50 feet?

Physics
1 answer:
Kazeer [188]3 years ago
4 0
106.68 centimetres are in 3.50 feet
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A ball has a mass of 1.5kg and is thrown straight up with a speed of 60m/s, what is the ball’s momentum:
madam [21]

Answer:

Assumption: the air resistance on this ball is negligible. Take g = 10\; \rm m \cdot s^{-2}.

a. The momentum of the ball would be approximately 60\;\rm kg \cdot m \cdot s^{-1} two seconds after it is tossed into the air.

b. The momentum of the ball would be approximately \rm \left(-45\; \rm kg \cdot m \cdot s^{-1}\right) three seconds after it reaches the highest point (assuming that it didn't hit the ground.) This momentum is smaller than zero because it points downwards.

Explanation:

The momentum p of an object is equal its mass m times its velocity v. That is: \vec{p} = m \cdot \vec{v}.

Assume that the air resistance on this ball is negligible. If that's the case, then the ball would accelerate downwards towards the ground at a constant g \approx -10\; \rm m \cdot s^{-2}. In other words, its velocity would become approximately 10\; \rm m \cdot s^{-1} more negative every second.

The initial velocity of the ball is 60\; \rm m \cdot s^{-1}. After two seconds, its velocity would have become 60\;\rm m \cdot s^{-1} + 2\; \rm s \times \left(-10\;\rm m \cdot s^{-1}\right) = 40\; \rm m \cdot s^{-1}. The momentum of the ball at that time would be around p = m \cdot v \approx 60\; \rm kg \cdot m \cdot s^{-1}.

When the ball is at the highest point of its trajectory, the velocity of the ball would be zero. However, the ball would continue to accelerate downwards towards the ground at a constant g \approx -10\; \rm m \cdot s^{-2}. That's how the ball's velocity becomes negative.

After three more seconds, the velocity of the ball would be 0\; \rm m \cdot s^{-1} + 3\; \rm s \times \left(-10\; \rm m \cdot s^{-2}\right) = -30 \; \rm m \cdot s^{-1}. Accordingly, the ball's momentum at that moment would be p = m \cdot v \approx \left(-45\; \rm kg \cdot m \cdot s^{-1}\right).

3 0
3 years ago
Which equation is used to calculate the weight of an object on a planet?
Kamila [148]

In this case to find the weight of an object you must use the formula.

W = mg

6 0
3 years ago
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A double concave lens is a ________ lens, and a double convex lens is a ______ lens.
forsale [732]

Answer:

b. diverging, converging

4 0
2 years ago
A 3.04 kg particle is located on the x-axis at xm = −8 m, and a 5.61 kg particle is on the x-axis at xM = 3.56 m. Find the coord
Murljashka [212]

Answer:

center of mass = −0.50 m

Explanation:

given data

mass m1 = 3.04 kg

distance xm = -8 m

mass m2 = 5.61 kg

distance xM = 3.56 m

solution

we get here center of mass for n mass of system that is express as

center of mass = \frac{m_1x_1+m_2x_2......m_nx_n}{m_1+m_2...m_n}     ......................1

but we have only 2 particle system so we will get

center of mass = \frac{m1 \times xm+m2 \times xM}{m1+m2}      .................2

put here value and we will get

center of mass = \frac{3.04 \times (-8 )+5.61 \times 3.56}{3.04 + 5.61}

solve it we will get

center of mass = −0.50 m

8 0
3 years ago
Maria makes a graphic organizer to compare open, closed, and short circuits. She adds the labels shown.
Lina20 [59]
The Answer is Label 1:Y Label 2: W
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3 years ago
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