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azamat
3 years ago
9

I need help with this problem :)

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

Replace all occurrences of y with 6x−3 in each equation.

Replace all occurrences of y in 18x−3y=9 with 6x−3 .

18x−3(6x−3)=9

y=6x−3

Simplify 18x−3(6x−3).

9=9

y=6x−3

Remove any equations from the system that are always true.

y=6x−3

Step-by-step explanation:

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4 years ago
Simplify the expression. Write your answer as a power.<br><br> 8^10⋅8^4
topjm [15]

8^14 is the answer.

This is because since they both have the same base, the exponents could be added together if the numbers are multiplied together

3 0
3 years ago
Read 2 more answers
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
Which ordered pair is a solution of the equation? 2x+4y=6x-y OPTION A: Only (4,5) OPTION B: Only (5,4) OPTION C Both A and B OPT
sammy [17]

Answer:

option b

Step-by-step explanation:

replace x and y with the x and y of the ordered pair

option a: 2(4)+4(5)=6(4)-5

solve

8+20=24-5

28=19  not true

option b:2(5)+4(4)=6(5)-4

solve

10+16=30-4

26=26  true

6 0
3 years ago
A plastics manufacturer has developed a new type of plastic trash can and proposes to sell them with an unconditional 6-year war
gtnhenbr [62]

Answer:

since -3.73 is less than 1.645, we reject H₀.    

Therefore this indicate that the proposed warranty should be modified

Step-by-step explanation:

Given that the data in the question;

p" = 13/20 = 0.65

Now  the test hypothesis;

H₀ : p = 0.9

Hₐ : p < 0.9

Now lets determine the test statistic;

Z = (p" - p ) / √[p×(1-p)/n]

= (0.65 - 0.9) /√[0.9 × (1 - 0.9) / 20]  

= -0.25 / √[0.9 × 0.1 / 20 ]

= -0.25 / √0.0045

= -0.25 / 0.067

= - 3.73

Now given that a = 0.05,

the critical value is Z(0.05) = 1.645 (form standard normal table)

Now since -3.73 is less than 1.645, we reject H₀.    

Therefore this indicate that the proposed warranty should be modified

3 0
3 years ago
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