Answer:
d(apart are the ships)=42.8 meters
Step-by-step explanation:
Given data
h (height)=38m
Ф₁=53°
Ф₂=28°
d(how far apart are the ships)=?
Solution
d₅₃°(distance to ship at 53°)=h/tanФ₁
d₅₃°=38/tan(53°)
d₅₃°=28.6m
now
d₂₈°(distance to ship at 28°)=h/tanФ₂
d₂₈°=38/tan(28°)
d₂₈°=71.4m
d(apart are the ships)=d₂₈°-d₅₃°
d(apart are the ships)=71.4-28.6
d(apart are the ships)=42.8 meters
a is the correct answer I Hope it help
The function g(x)=4(x+3)² - 68 is mapped to 32.
<h3>What is equation?</h3>
An equation is a mathematical expression in terms of one or more unknown variable.
Given are the following functions:
f(x)= - 3x² - 4
g(x)= 4(x+3)²-68
f(x)= 3x
f(x)= 2x-62
To get the mapped function, we substitute the value of x in all function,
a) f(x)=-3x²- 4
Put x=2,
f(2)= -3 (2)² - 4
f(2)= -16
It is not mapped.
b) g(x)=4(x+3)² - 68
Put x=2,
g(2) = 4(2+3)² - 68
g(x) =32
It is mapped to 32.
c) f(x)=3x
Put x=2,
f(2) = 3 x 2 =6
It is not mapped.
d) f(x)=2x - 62
Put x=2,
f(2) =2x2 -62
f(2) = -58
It is not mapped.
Therefore, the function g(x)=4(x+3)² - 68 is mapped to 32.
Learn more about equations.
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First thing to do is to solve each of these for y. The first one is y=-4x-3; the second one is y=4x-21; the third one is y=4x+21; the fourth one is y=-4x+3. From that you can tell the positive slopes are found in the second and third equations. Those are the ones we will test now for the point (3, -9). y=-9 and x=3, so let's fill in accordingly. The second equation filled in is -9=4(3)-21. Does the left side equal the right when we do the math? -9=12-21 and -9=-9. So the second one works. Just for the sake of completion, let's do the same with the third: -9=4(3)+21. Does -9=12+21? Of course it doesn't. Our equation is the second one above, y+9=4(x-3).
