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2 years ago

Dalton incorporated the law of conservation of mass into his atomic theory by asserting that

Chemistry

1 answer:

Feliz [49]2 years ago

7 0

Answer:

a. atoms are indivisible. ... atoms can not be destroyed in chemical reactions.

Explanation:

Hope this helped :D

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How many moles of H3PO4 would produce 12 moles of water in this reaction? ЗKOH + H3PO4 K3PO4 + 3H20

Olenka [21]

Answer:

4 moles of H₃PO₄

Explanation:

The reaction expression is given as;

3KOH + H₃PO₄ → K₃PO₄ + 3H₂O

Number of moles of water = 12moles

Unknown:

Number of moles of H₃PO₄ = ?

Solution:

From the balanced reaction expression we see that;

3 moles of water is produced from 1 mole of H₃PO₄

So; 12 moles of water would be produced from $\frac{12}{3}$ = 4 moles of H₃PO₄

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2 years ago

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What is the penetrating power of beta

zlopas [31]

The penetrating power of alpha rays, beta rays, and gamma rays varies greatly. Alpha particles can be blocked by a few pieces of paper. Beta particles pass through paper but are stopped by aluminum foil. Gamma rays are the most difficult to stop and require concrete, lead, or other heavy shielding to block them.

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3 years ago

An inflatable toy starts with 1.05 moles of air and a volume of 5.17 liters. When fully inflated, the volume is 8.00 liters. If

padilas [110]

Answer:- 1.62 moles

Solution:- At constant temperature and pressure, volume is directly proportional to the moles of the gas.

$\frac{V_1}{V_2}=\frac{n_1}{n_2}$

from given data, $V_1$ = 5.17 L, $n_1$ = 1.05 moles

$V_2$ = 8.00 L, $n_2$ = ?

Let's plug in the values in the formula:

$\frac{5.17L}{8.00L}=\frac{1.05moles}{n_2}$

On cross multiply:

$n_2=\frac{8.00L(1.05moles)}{5.17L}$

$n_2$ = 1.62 moles

So, now the toy contains 1.62 moles of the air.

5 0

3 years ago

What is the attractive force between two of the same kind of particle?

My name is Ann [436]

Answer: The force which exists between particle of same kind of substance called cohesion force. A . B . The force of cohesion is defined as the force of attraction between molecules of the same substance.

Explanation:

8 0

3 years ago

A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0- L vessel at 300 K . The following equilibr

umka2103 [35]

Answer:

The concentration of N2 at the equilibrium will be 0.019 M

Explanation:

Step 1: Data given

Number of moles of NO = 0.10 mol

Number of moles of H2 = 0.050 mol

Number of moles of H2O = 0.10 mol

Volume = 1.0 L

Temperature = 300K

At equilibrium [NO]=0.062M

Step 2: The balanced equation

2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

Step 3: Calculate the initial concentration

Concentration = Moles / volume

[NO] = 0.10 mol / 1L = 0.10 M

[H2] = 0.050 mol / 1L = 0.050 M

[H2O] = 0.10 mol / 1L = 0.10 M

[N2] = 0 M

Step 4: Calculate the concentration at the equilibrium

[NO] at the equilibrium is 0.062 M

This means there reacted 0.038 mol (0.038M) of NO

For 2 moles NO we need 2 moles of H2 to produce 1 mol N2 and 2 moles of H2O

This means there will also react 0.038 mol of H2

The concentration at the equilibrium is 0.050 - 0.038 = 0.012 M

There will be porduced 0.038 moles of H2O, this means the final concentration pf H2O at the equilibrium is 0.100 + 0.038 = 0.138 M

There will be produced 0.038/2 = 0.019 moles of N2

The concentration of N2 at the equilibrium will be 0.019 M

5 0

3 years ago