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Phoenix [80]
3 years ago
15

What is the exact standard temperature degree and unit?

Chemistry
1 answer:
andriy [413]3 years ago
3 0
Standard temperature is zero degrees Celsius. This is the point at which water freezes.
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Is a substance that a filter can seperate into two parts a mixture or a pure substance?
jok3333 [9.3K]
Mixture. Mixtures can be separated into their component parts, while substances are chemically bonded atoms that can't be separated by physical means.
7 0
3 years ago
Can someone help me with my chemistry problem?
insens350 [35]

Answer:

D. 108g of water

Explanation:

16g CH4 produces 2(18)g of H20

1g CH4 produces \frac{36}{16}g of H2O

48g CH4 produces \frac{36}{16}×48

                                108g of H20

8 0
2 years ago
when a reactive metal is added to water, bubbles or fizzing can be observed. Explain the appearance of the bubbles​
MakcuM [25]

Answer:

This is because of the release of hydrogen gas in the reaction.

Explanation:

Metals react with water and produce a metal oxide and hydrogen gas. It also starts floating due to the bubbles of hydrogen gas sticking to its surface.

For eg:

<u>2Mg. + 2H2O --------> 2MgOH + H2</u>

Here,

Metal taken is <u>magnesium(2Mg)</u> which when reacts with <u>water(2H2O)</u> to form its <u>oxide form (2MgOH)</u> and <u>hydrogen gas(H2)</u> is released which comes outside water as bubbles.

7 0
3 years ago
What's the formula equation for the reaction that occurred between the barium chloride solution , BaCl2 (aq), and the sodium sul
Solnce55 [7]
The balanced equation is:

BaCl2 (aq) + Na2SO4 (aq) ----> BaSO4(s)+ 2 NaCl(aq)

This is a double replacement reaction.

The reactants are:

a) BaCl2: barium chloride, a ionic compound, therefore soluble in water,

b) Na2SO4: sodium sulfate, another ionic compound, therefore also soluble in water.

The products are:

c) BaSO4: barium sulfate, a solid not soluble in water which precipitates.

d) NaCl: sodium chloride, an ionic compound, therefore soluble in water.
4 0
3 years ago
Ethanol (c2h5oh) melts at -114°c. the enthalpy of fusion is 5.02 kj/mol. the specific heats of solid and liquid ethanol are 0.9
maria [59]
You'll want to add three amounts of heat. 

(1) Specific heat of lowering the temperature from -135°C to the melting point -114°C
(2) Latent heat of fusion/melting
(3) Specific heat of elevating the temperature from -114°C to -50°C

(1) E = mCΔT = (25 g)(0.97 J/g·°C)(1 kJ/1000 J)(-114 - -135) = 0.509 kJ
(2) E = mΔH = (25 g)(5.02 kJ/mol)(1 mol/46.07 g ethanol) = 2.724 kJ
(3) E = mCΔT = (25 g)(2.3 J/g·°C)(1 kJ/1000 J)(-50 - -114) = 3.68 kJ

<em>Summing up all energies, the answer is 6.913 kJ.</em>
7 0
3 years ago
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