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Romashka [77]
3 years ago
14

Volumeof Cone with a height of 9 cm and radius of 3 cm

Mathematics
1 answer:
Naily [24]3 years ago
5 0

Answer:

i think this is the answer not 100 percentage sure V≈84.82cm³

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If you place a 20 ft ladder 4ft from the base of the wall. How high up will it reach? Round answer to the nearest tenth
xeze [42]

Answer:

h = 19.6 ft

Step-by-step explanation:

Given that,

A 20 ft ladder 4ft from the base of the wall.

The height of the ladder, H = 20 ft

The base distance, b = 4 ft

We need to find the height of the reach. Let it is P.

Using Pythagoras theorem,

H^2=b^2+P^2\\\\P=\sqrt{H^2-b^2}\\\\P=\sqrt{20^2-4^2}\\\\=19.59\ ft

or

P = 19.6 ft

So, the height is 19.6 ft.

7 0
3 years ago
Expand and simplify: (13i-9)^5
Softa [21]

Answer:

−112284−981812i

6 0
3 years ago
When do you reject the null hypothesis?
Nimfa-mama [501]

You reject the Null Hypothesis when you have a small P-Value. Here is an example! Also we never accept the null hypothesis, think of it like this if we bring someone to court you wouldn't say their innocent of a crime, you only know that if they do not get convicted of the crime they are not guilty in the eyes of the law. Same thing applies here, since there could be several answers that satisfy our assumptions made, we can not be certain that 1 of those assumptions is the REAL answer it's just AN answer.

6 0
3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
Which polynomial is in standard form?
Tamiku [17]

Answer:

D). 5x^7y^2+7x^6y^5-14x^3y^7+51x^2y^9

Step-by-step explanation:

For better clarity let us re write the options

A).2xy^3+3x^3y^4-4x^4y^5+9x^5y^6

B).8x^5-5y^4-2xy^5+x^2y

C).x^3y^2-3x^2y-9x^4y^3+11x

D).5x^7y^2+7x^6y^5-14x^3y^7+51x^2y^9

To express polynomial with mixed variables in standard form, we begin by the highest coefficient of x to the smallest (we place high precedence on the coefficient  x terms)

5 0
3 years ago
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