Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given
![\therefore y=\dfrac{2}{3}\times x-4](https://tex.z-dn.net/?f=%5Ctherefore%20y%3D%5Cdfrac%7B2%7D%7B3%7D%5Ctimes%20x-4)
Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.
![m1\times m2=-1](https://tex.z-dn.net/?f=m1%5Ctimes%20m2%3D-1)
Substituting m1 we get m2 as
![\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B2%7D%7B3%7D%5Ctimes%20m2%3D-1%5C%5C%5C%5Cm2%3D-%5Cdfrac%7B3%7D%7B2%7D)
Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Cube i think sorry if its wrong
Answer:
similar and congruent
Step-by-step explanation:
those are the only words i know
Answer:
14
Step-by-step explanation:
Distance between y2 = x + 8 and y1 = x - 6
y2 - y1 = (x + 8) - (x - 6) = 14
Answer:
256.8
Step-by-step explanation:
the tenths place is the first number after the decimal.