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3 years ago

Label A is showing_ frequency waves, and label B is showing _ frequency waves

Chemistry

1 answer:

igomit [66]3 years ago

6 0

It's not really possible to tell longitudinal vs. transverse in this image as given. However, we can say that the waves labeled A are high-frequency (short wavelengths) while the waves labeled B are low-frequency (long wavelengths). So, this third answer choice would be correct here.

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Which compounds are electrolytes

KengaRu [80]

Answer:

Calcium.

Potassium.

Chlorine.

Magnesium.

Sodium.

Phosphate.

Explanation:

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2 years ago

3. Jasmine pousse un objet sur une distance de

BARSIC [14]

Jasmine pushes an object a distance of 15 m at constant speed. It produces a 450J of work on the object. What strength Jasmine does it exert on the object?

Answer:

30J

Explanation:

Given parameters:

Distance moved = 15m

Work done = 450J

Unknown:

Strength Jasmine applied = ?

Solution:

The strength Jasmine applied or exerted on the object is the force of pull that cause the motion of the object and the distance it was moved.

Now;

Work done = Force x distance

So;

450 = Force x 15

Force = $\frac{450}{15}$ = 30J

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2 years ago

If a mineral is opaque, lustrous, malleable, and can conduct heat and electricity, it is a(n) ________. A) element B) gemstone C

bulgar [2K]

Answer:

If a mineral is opaque, lustrous, malleable, and can conduct heat and electricity, it is a "Metal"

D) Metal

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2 years ago

1 mole of CH4 contains ________molecules

laila [671]

1 mole contains 6.023 *10^23 molecules

7 0

3 years ago

A student has a 0.00124 M HCl (aq) solution and she titrates 25.00 mL of this solution against an unknown potassium hydroxide so

malfutka [58]

Answer:

The Molarity of KOH is

$7,01.10^{-4}M$

Explanation:

The endpoint indicates the volume necessary to neutralize the moles of acid.

In other words, the point at which the moles of both solutions are the same.

$M_{(HCl)}V_{HCl}=n\\ \\M_{(KOH)}V_{KOH}=n$

we match these equations and find the concentration of KOH

$M_{(HCl)}. V_{(HCl)} =M_{(KOH)} .V_{(KOH)}\\ \\M_{(KOH)}=\frac{M_{(HCl)}. V_{(HCl)}}{V_{(KOH)}} \\\\M_{(KOH) =\frac{(25mL)(0,00124m)}{(44,25mL)}\\\\$

$M_{(KOH)}=7,01.10^{-4}$

5 0

3 years ago

Label A is showing___ frequency waves, and label B is showing ___ frequency waves

Label A is showing_ frequency waves, and label B is showing _ frequency waves