All categories

3 years ago

When the chemical energy in the coal is burned it is converted to.

Chemistry

2 answers:

Lunna [17]3 years ago

8 0

Answer:

Mechanical energy

Explanation:

because the heat energy turn into a mechanical energy that spins the engine

Dafna11 [192]3 years ago

7 0

Answer:

Heat Energy

Explanation:

You might be interested in

When the temperature in a room increases from 25°C to 33°C, changes from a solid to a liquid.

mr Goodwill [35]

Answer:

true

Explanation:

Because ice melts if the temperature increasese

8 0

3 years ago

If the length, width, and height of a box are 8.00 cm, 6.75 cm and 3.50 cm, respectively, what is the volume of the box in units

svp [43]

I think it is 1620 (lxwxh) x 10 to get to millimeters

5 0

3 years ago

Read 2 more answers

How many moles of water can be produced with 4.3 moles of H2 and 5.6 moles of O2? Which reactant is limiting? How many moles of

xeze [42]

Answer:

Hydrogen H₂ will be the limiting reagent.

The excess reactant that will be left after the reaction is 3.45 moles.

4.3 moles of water can be produced.

Explanation:

The balanced reation is:

2 H₂ + O₂ → 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

H₂: 2 moles
O₂: 1 mole
H₂O: 2 moles

To determine the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 1 mole of O₂ reacts with 2 moles of H₂, how much moles of H₂ will be needed if 5.6 moles of O₂ react?

$moles of H_{2} =\frac{5.6 moles of O_{2} *2 mole of H_{2} }{1 mole of O_{2}}$

moles of H₂= 11.2 moles

But 11.2 moles of H₂ are not available, 4.3 moles are available. Since you have less moles than you need to react with 5.6 moles of O₂, hydrogen H₂ will be the limiting reagent and oxygen O₂ will be the excess reagent.

Then you can apply the following rules of three:

If by reaction stoichiometry 2 moles of H₂ react with 1 mole of O₂, 4.3 moles of H₂ will react with how many moles of O₂?

$moles of O_{2} =\frac{1 mole of O_{2} *4.3 mole of H_{2} }{2 mole of O_{2}}$

moles of O₂= 2.15 moles

The excess reactant that will be left after the reaction can be calculated as:

5.6 moles - 2.15 moles= 3.45 moles

The excess reactant that will be left after the reaction is 3.45 moles.

If by reaction stoichiometry 2 moles of H₂ produce 2 moles of H₂O, 4.3 moles of H₂ produce how many moles of H₂O?

$moles of H_{2}O =\frac{2 moles of H_{2}O *4.3 mole of H_{2} }{2 mole of H_{2}}$

moles of H₂O= 4.3 moles

4.3 moles of water can be produced.

8 0

2 years ago

At a certain temperature, 4.0 mol NH3 is introduced into a 2.0 L container, and the NH3 partially dissociates by the reaction. 2

xxMikexx [17]

Answer:

K = 3.37

Explanation:

2 NH₃(g) → N₂(g) + 3H₂(g)

Initially we have 4 mol of ammonia, and in equilibrium we have 2 moles, so we have to think, that 2 moles have been reacted (4-2).

2 NH₃(g) → N₂(g) + 3H₂(g)

Initally 4moles - -

React 2moles 2m + 3m

Eq 2 moles 2m 3m

We had produced 2 moles of nitrogen and 3 mol of H₂ (ratio is 2:3)

The expression for K is: ( [H₂]³ . [N₂] ) / [NH₃]²

We have to divide the concentration /2L, cause we need MOLARITY to calculate K (mol/L)

K = ( (2m/2L) . (3m/2L)³ ) / (2m/2L)²

K = 27/8 / 1 → 3.37

5 0

3 years ago

Read 2 more answers

A saturated solution of calcium hydroxide contains 1.85 g of solute in 100. mL of solution. What is its molarity

Leona [35]

Answer:

$M=0.250M$

Explanation:

Hello!

In this case, since the molarity of a solution is computed by dividing the moles of solute by the volume of solution in liters, we first need to compute the moles of solute knowing that the molar mass of calcium hydroxide is 74.1 g/mol as follows:

$n=1.85g*\frac{1mol}{74.1g}=0.0250mol$

Next, since the 100-mL solution is also expressed in liters by 0.100 L, we directly compute the molarity as shown below:

$M=\frac{0.0250mol}{0.100L}\\\\M=0.250M$

Which is expressed in molar units that are mol/L.

Best regards!

8 0

3 years ago