Oxidation number is defined as the total number of electrons that are gained or lost by the atom to form a chemical bond.
the oxidation number of the compound H₂S is 0.
the sum of the oxidation numbers of the individual elements should add up to the oxidation number of the compound.
(oxidation number of H x 2 H ions) + oxidation number of S = 0
since we know the oxidation number of H, lets name the oxidation number of S = x
(+1 * 2 )+ (x) = 0
2 + x = 0
x = -2
oxidation number of S is -2
<u>Answer:</u> The below calculations proves that the rate of diffusion of
is 0.4 % faster than the rate of diffusion of 
<u>Explanation:</u>
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

We are given:
Molar mass of 
Molar mass of 
By taking their ratio, we get:


From the above relation, it is clear that rate of effusion of
is faster than 
Difference in the rate of both the gases, 
To calculate the percentage increase in the rate, we use the equation:

Putting values in above equation, we get:

The above calculations proves that the rate of diffusion of
is 0.4 % faster than the rate of diffusion of 
Answer:
The answer I believe is B. Erosion
Explanation:
Just sounds better than all the other choices.
The answer to the question