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zavuch27 [327]
3 years ago
14

at what temperature will you find more potassium nitrate(kno3) in 100 g of H2O . In other words at which temperature will you ha

ve a higher solubility: 10c , 20c , 50c , 85c ?
Chemistry
1 answer:
Oksana_A [137]3 years ago
4 0
The answer to this question would be: <span>85c 
</span>Solubility is influenced by the temperature of the molecule. Higher temperature will result in a higher solubility. That is why brewing using hot water will be easier than using cold water. Higher temperature also means higher reaction rate.
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How is the atomic mass of an element calculated? A. by determining the number of electrons in the outer orbital B.by determining
Vaselesa [24]

By adding together the number of protons and neutrons and multiplying by 1 amu, you can calculate the mass of the atom.

7 0
3 years ago
Read 2 more answers
A chemist measures the energy change ?H during the following reaction:
slamgirl [31]

Answer:

Endothermic

It absorbs heat

1.20 × 10³ kJ

Explanation:

Let's consider the following thermochemical equation.

2 H₂O(l) → 2 H₂(g) + O₂(g)    ΔH = 572 kJ

Since ΔH > 0, the reaction is endothermic, that is, it absorbs heat when H₂O reacts.

572 kJ are absorbed when 36.03 g of water react. The heat absorbed when 75.8 g of H₂O react is:

75.8 g H₂O × (572 kJ/36.03 g H₂O) = 1.20 × 10³ kJ

5 0
3 years ago
A eraser has a mass of 4g and a volume of 2cm3 what is it’s density
sladkih [1.3K]

Answer:

<h3>The answer is 2.0 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 4 g

volume = 2 cm³

We have

density =  \frac{4}{2}  \\

We have the final answer as

<h3>2.0 g/cm³</h3>

Hope this helps you

4 0
3 years ago
Lead has a density of 11.29 g/mL. If you had 186 g of lead, what would its volume be?
Varvara68 [4.7K]
I think you just do 11.29 multiplied by 186 since to find density you divide mass by volume. So 186 divided by x is 11.29. So in conclusion the volume would be 2,099.94mL
8 0
3 years ago
Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfe
babunello [35]

Answer:

Oxidized and reducing agent: manganese.

Reduced and oxidizing agent: mercury.

Explanation:

Hello!

In this case, for the reaction:

Hg^{2+}(aq) + Mn^0(s)\rightarrow Hg(s) + Mn^{2+}(aq)

We keep in mind that the species that increase the oxidation state is the oxidized one whereas the one that decrease the oxidation state is the reduced one; therefore manganese is the oxidized one as well as the reducing agent because it goes from 0 to +2 and mercury the reduced one as well as the oxidizing agent because it goes from 2+ to 0.

Best regards

6 0
2 years ago
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