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Leya [2.2K]
2 years ago
10

X^2-x-12 factor completely

Mathematics
1 answer:
steposvetlana [31]2 years ago
5 0
Use the sum-product pattern

2
−

−
1
2
x
2
−
x
−
12
x2−x−12

2
+
3

−
4

−
1
2
x
2
+
3
x
−
4
x
−
12
x2+3x−4x−12
2
Common factor from the two pairs

2
+
3

−
4

−
1
2
x
2
+
3
x
−
4
x
−
12
x2+3x−4x−12

(

+
3
)
−
4
(

+
3
)
x
(
x
+
3
)
−
4
(
x
+
3
)
x(x+3)−4(x+3)
3
Rewrite in factored form

(

+
3
)
−
4(+3)x
(x+3)−4(x+3)
x(x+3)−4(x+3)
(−4)(+3)
(x−4)(x+3)
(x−4)(x+3)
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Step-by-step explanation:

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

3t + 7 = 2 + 5t

<u>Step 2: Solve for </u><u><em>t</em></u>

  1. [Subtraction Property of Equality] Isolate <em>t</em> terms:                                        7 = 2 + 2t
  2. [Subtraction Property of Equality] Isolate <em>t</em> term:                                         5 = 2t
  3. [Division Property of Equality] Isolate <em>t</em>:                                                        5/2 = t
  4. Rewrite:                                                                                                             t = 5/2
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