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Norma-Jean [14]
2 years ago
5

A current of 3.75 A in a long, straight wire produces a magnetic field of 2.61 μT at a certain distance from the wire. Find thi

s distance.
Physics
1 answer:
Bad White [126]2 years ago
5 0

Given :

Current, I = 3.75 A .

Magnetic Field, B = 2.61\times 10^{-4}\ T

To Find :

The distance from the wire.

Solution :

We know,

B = K\dfrac{2i}{d}\\\\d = 10^{-7}\times \dfrac{2\times 3.75}{2.61\times 10^{-4}}\\\\d =  0.00287\ m \\\\d = 2.87\times 10^{-3}\ m

Hence, this is the required solution.

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that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

Explanation:

Let us carefully analyze the situation, when the bar is facing the index post a load of equal magnitude, but opposite sign on its surface, these two charges are in balance; When the hand touches the pole, it creates a path to the ground where the charges that were induced on the pole can be balanced with the charge coming from the ground, leaving a zero charge on the pole.

 

   Now if the hand is removed, there can be no exchange of charges with the earth. When the bar is removed, the induced loads are redistributed in the post, but the excess loads that came from the earth that have the same value and are of a sign opposite to the induced ones remain, you want to sign that they are of the same sign as the charges of the bar.

   In summary, after the process, the post has a load of equal magnitude and sign (negative) that of the bar.

   If we assume that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

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3 years ago
What do you think are some differences between sound waves traveling through air versus traveling through water?
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3 years ago
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Serhud [2]

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Transverse

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That leaves tranverse waves, the ones we're most used to, since they look very "wavelike," with smooth peaks and valleys. Electromagnic waves behave like these, oscillating in a plane perpendicular to the direction they're traveling in.

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What is the horse power of an electric motor which can do by 1250 joule of work in 5 seconds​
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1250 J in 5 sec= 250 Joule(s) per second (1250/5 0

250 Joules per second = 250 Watts ( 1J/s = 1 Watt per definition)

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