Answer:
V’/V= 1.05
Explanation:
The density is defined with the ratio of the mass to the volume, for the fish with the collapsed sack
ρ₁ = m / V
The density of the fish with the bag full of air is
ρ₂ = m / V’
For the fish to float if it exerts its density must be exactly equal to that of the surrounding water
We clear the mass and match
m = ρ1 V = ρ2 V'
ρ₁ V = ρ₂ V’
V ’/ V = ρ₁ / ρ₂
V ’/ V = 1.05 / 1
V ’= 1.05 V
This is that the fish should increase its volume by 5%
They absorb the energy of seismic waves.
Explanation:
Base - isolators, rubber and steel pads under buildings reduces earthquake damage by absorbing the energy of seismic waves.
- Earthquakes are produced by the sudden release of energy within the earth which causes displacement and sharp movement on earth surface.
- There are four main types of waves that are propagated by seismic waves which wrecks havoc.
- Understanding the waves and their properties has been useful in designing earthquake resistant structures.
- Base-isolators, rubber and steel pads helps to absorb seismic waves.
- When seismic waves are absorbed, they are cut off.
- This way they cannot cause damage.
learn more:
Earthquake brainly.com/question/6520403
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Answer:
v = 719.2 m / s and a = 83.33 m / s²
Explanation:
This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is
v - v₀ = 
ln (M₀ / M)
where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket
In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s
m_fuel = 75 10
m_fuel = 750 kg
As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is
M = 3000 -750 = 2250 kg
let's calculate
v - 0 = 2500 ln (3000/2250)
v = 719.2 m / s
To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is
Push = v_{e} dM / dt
let's calculate
Push = 2500 75
Push = 187500 N
If we use Newton's second law
F = m a
a = F / m
let's calculate
a = 187500/2250
a = 83.33 m / s²
Answer:
After 1 sec = 4.9 m
After 2 sec = 19.6 m
After 3 sec = 44.1 m
After 4 sec = 78.4 m
After 5 sec = 122.5 m
Explanation:
After 1 sec:
<em>u=0m/s t=1 s a=9.8m/s²</em>
s = ut + (1/2)at²
=0(1) + (1/2)(9.8)(1²) = 4.9m
After 2 sec:
<em>u=0m/s t=2 s a=9.8m/s²</em>
s = ut + (1/2)at²
=0(2) + (1/2)(9.8)(2²) = 19.6m
After 3 sec:
<em>u=0m/s t=3 s a=9.8m/s²</em>
s = ut + (1/2)at²
=0(3) + (1/2)(9.8)(3²) = 44.1m
After 4 sec:
<em>u=0m/s t=4 s a=9.8m/s²</em>
s = ut + (1/2)at²
=0(4) + (1/2)(9.8)(4²) = 78.4m
After 5 sec:
<em>u=0m/s t=5 s a=9.8m/s²</em>
s = ut + (1/2)at²
=0(5) + (1/2)(9.8)(5²) = 122.5m
