Answer:
B. The approximate length of EF is 4.47 units, and the approximate perimeter of triangle EFG is 12.94 units.
Step-by-step explanation:
First step is to determine the length of EF, since that will give us 2 sides of the triangle (since EG = EF).
From the diagram, we can easily make a rectangle triangle by dropping a vertical line from vertex E, let's name Z the meeting point of that line with the segment GF. Then we have a rectangle triangle EZF with a height of 4 and a base of 2, of which EF is the hypotenuse. So...
EF² = 4² + 2² = 16 + 4 = 20
EF = √20 = 4.47
Now that we have EF, we also have EG:
EF = 4.47
EG = 4.47
GF = 4 (visible on the graph)
Perimeter = 4.47 + 4.47 + 4 = 12.94 units.
Answer: f(x)=
has all real value as its domain.
Explanation: since, we have three functions f(x)=
,
while g(x) and p(x) are line segments.
Now, g(x) is a function by a line segment which passes through two points (-1.8,-3) and ( 1,3.8).
Thus it is clear that its domain will be the ends points. so domain of the function g(x) will be [-1.8, 3.8] which is the subset of real numbers set (R).
Similarly, domain of function p(x) will be [1.7, 1], which is also the subset of R.
But, when we talk about f(x) it contains all the possible value of x. Thus we can say that
has R as its domain.
Answer:
9.85
Step-by-step explanation:
I hate these, LOL
We're going to draw a triangle on the graph paper to solve this. (in theory)
The top point is at 2 on the x axis, and the bottom is at 6. That's a difference of 4. Draw a line from the top dot over 4 spaces, so a line dropped from there could go straight to the bottom dot. We'll call this line/side of the triangle a, and a = 4.
Then we drop the line from there (6, 4) down to the second dot at (6, -5). That line is 9 places long. We'll call this line/side of the triangle b, and b = 9.
(This is so much easier to draw than type, I'll attach a picture).
Then we connect the two dots diagonally to form line/side c of our triangle. This is the length we don't know.
The pythagorean theorem says a^2 + b^2 = c^2
So a = 4, b = 9, c is unknown for our triangle
(4)(4) + (9)(9) = c^2
16 + 81 = 97
The square root of 97 = 9.8488, so if they have you round, I would say 9.85
Sorry if this just confused you more.
Answer:
So the perimeter is 2(16+x) or 32+2x. The area is 8(x+8) or 8x+64.
Step-by-step explanation: