Given :
- The 8 grade class is selling pennants and flags.
- They earn $1 for each pennant
- sold and $6 for each flag sold.
- They sell 50 items and earn $115.
To Find :
- How many pennants and how many flags did they sell?
Solution :-
<u>Let </u><u>us</u><u> </u><u>take </u><u>that </u><u>,</u>
→ number of flags sold = f
→ number of pennant sold = p
<u>Money </u><u>earned</u><u> </u><u>by</u><u> </u><u>selling</u><u> </u><u>flags</u><u> </u>
→ Money = $6 * f = $6f
<u>Money</u><u> </u><u>earned</u><u> by</u><u> selling</u><u> </u><u>pennants</u>
→ Money = $1*p = $1p
<u>Total</u><u> </u><u>money</u><u> </u><u>earned</u><u> </u>
→ Total Money = $6f + $1p
<u>Total </u><u>items </u><u>sold </u>
→ Total items = f + p = 50 . . . . . (i)
<u>According</u><u> to</u><u> the</u><u> question</u><u> </u><u>,</u>
→ 6f + p = 115 . . . . . (ii)
<u>Solving</u><u> </u><u>equations</u><u> (</u><u>i)</u><u> </u><u>and </u><u>(</u><u>ii)</u><u> </u><u>,</u>
On subtracting them ,
→ 6f - f = 115 -50
→ 5f = 65
→ f = 65/5
→ f = 13
<u>Substitute</u><u> </u><u>this </u><u>in </u><u>equation</u><u> </u><u>(</u><u>i)</u><u> </u><u>,</u>
→ 13 + p = 50
→ p = 50 -13 = 37
<u>Hence</u><u> th</u><u>e</u><u>y </u><u>sold </u><u>1</u><u>3</u><u> </u><u>flags</u><u> </u><u>and </u><u>37</u><u> </u><u>pennants</u><u> </u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em>