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Rashid [163]
3 years ago
15

A train is travelling at 50 m s−1 when the driver applies the brakes and gives the train a constant deceleration of magnitude 0.

50 m s−2 for 100 s. Describe what happens to the train. Calculate the distance travelled
Physics
1 answer:
ryzh [129]3 years ago
3 0

Answer:

The strain will come to rest after traveling some distance.

distance traveled = 2500 m

Explanation:

The strain will come to rest after traveling some distance.

Applying,

s = ut+at²/2................... Equation 1

Given: u = initial velocity, a = deceleration, t = time, s = distance

From the question,

Given: u = 50 m/s, t = 100s, a = -0.5 m/s²(deceleration)

Substitute these values into equation 1

s = 50(100)+(-0.5)(100²)/2

s = 5000-2500

s = 2500 m

Hence the distance traveled is 2500 m

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Based on Newton's law of motion, which combination of rocket bodies and engine will result in the acceleration of 40 m/s ^2 at t
ad-work [718]

The question is incomplete. The complete question is :

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.

Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?

Body 3 + Engine 1

Body 2 + Engine 2

Body 1 + Engine 2

Body 1 + Engine 1

Solution :

Given :

Body       Mass (gram)     Engine      Force (newtons)

1                   500                 1                     25

2                  1500                2                    20

3                  750                  3                    30

The body 1 has a mass of 500 gram which is equal to 0.5 kg

And engine 2 has a force of 20 newtons.

We know that according to Newton's laws of motion,

Force = mass x acceleration

 20    = 0.5 x acceleration

Acceleration $=\frac{20}{0.5}$

                      $=\frac{200}{5}$

                      $= 40 \ m/s^2$

Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of $ 40 \ m/s^2$ at the start of the launch.

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