Answer:
τ = 1679.68Nm
Explanation:
In order to calculate the required torque you first take into account the following formula:
(1)
τ: torque
I: moment of inertia of the merry-go-round
α: angular acceleration
Next, you use the following formulas for the calculation of the angular acceleration and the moment of inertia:
(2)
(3) (it is considered that the merry-go-round is a disk)
w: final angular speed = 3.1 rad/s
wo: initial angular speed = 0 rad/s
M: mass of the merry-go-round = 432 kg
R: radius of the merry-go-round = 2.3m
You solve the equation (2) for α. Furthermore you calculate the moment of inertia:
![\alpha=\frac{\omega}{t}=\frac{3.1rad/s}{2.1s}=1.47\frac{rad}{s^2}\\\\I=\frac{1}{2}(432kg)(2.3)^2=1142.64kg\frac{m}{s}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7B%5Comega%7D%7Bt%7D%3D%5Cfrac%7B3.1rad%2Fs%7D%7B2.1s%7D%3D1.47%5Cfrac%7Brad%7D%7Bs%5E2%7D%5C%5C%5C%5CI%3D%5Cfrac%7B1%7D%7B2%7D%28432kg%29%282.3%29%5E2%3D1142.64kg%5Cfrac%7Bm%7D%7Bs%7D)
Finally, you replace the values of the moment of inertia and angular acceleration in the equation (1):
![\tau=(1142.64kgm/s)(1.47rad/s^2)=1679.68Nm](https://tex.z-dn.net/?f=%5Ctau%3D%281142.64kgm%2Fs%29%281.47rad%2Fs%5E2%29%3D1679.68Nm)
The required torque is 1679.68Nm
Answer:
it is placed 9th in the periodic table
it is in the the 7th column and the 2nd period
it is a gas
it valence shell has 7 electrons and it can take 1 electron during ionic bonding
Explanation:
this is all that can into my mind. hope it helps
Answer:
V2 = (V1 - u) / (1 - V1 u / c^2)
V1 = speed of ship in observer frame = .99 c to right
u = speed of frame 2 = -.99 c to left relative to observer
V2 = speed of V1 relative to V2
V2 = (.99 - (-.99 ) / (1 - .99 (-.99)) c
V2 = 1.98 / (1 + .99^2) c = .99995 c
I think if I was a researcher I would review my work or the sources I use, True
As the wave travels through different media, its speed and wavelength change, and its frequency remains constant.
mark brainliest :)