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goldfiish [28.3K]
3 years ago
10

Through which of the following can magnetic force pass

Physics
2 answers:
laiz [17]3 years ago
8 0
All of the above hope this helps :)
Stells [14]3 years ago
7 0
All of the above hope this helps
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A toy of mass 0.155 kg is undergoing simple harmonic motion (SHM) on the end of a horizontal spring with force constant 305 N/m
zzz [600]

Answer:

310.38\times 10^{-4}j

Explanation:

We have given mass m=0.155 kg

Force constant K = 305 N/m

Distance X=1.25\times 10^{-2}m

Velocity v=.305 m/sec

The total energy at any position of the motion is give by E=\frac{1}{2}mv^2+KX^2  here \frac{1}{2}mv^2 is energy due to motion and KX^2  is energy due to spring elongation

So total energy E=\frac{1}{2}\times 0.155\times 0.305^2+305\times 0.0125^2=310.38\times 10^{-4}j

4 0
2 years ago
Calculate the mass of the earth if the radius of the earth is 6.38 × 10^6​
Delicious77 [7]

Answer:

C

Explanation:

C is i thing

7 0
2 years ago
If a questions says "at what point does the ball stop?" what is it asking for?
Bad White [126]

Explanation:

If a question says "at what point does the ball stop?", it means we need to find the position of the ball when its final velocity is equal to 0. It can be calculated using the equation of kinematics as follows :

d = ut + (1/2) at²

and

v²-u²=2ad

Where, u is initial velocity, v is final velocity, a is acceleration, t is time and d is displacement.

5 0
3 years ago
Where do cells get the chemicals needed to synthesize other molecules?
jek_recluse [69]
From the food they take in
4 0
3 years ago
Read 2 more answers
Assume the earth to be a nonrotating sphere with mass MEME and radius RERE. If an astronaut weights WW on the ground, what is hi
Solnce55 [7]

Answer:

The weight at a distance 2 RE from surface of earth is <em>W/9</em>

Explanation:

For the value of acceleration due to gravity (g), we have a formula, that is:

g = (G)(ME)/(RE)²    ----- equation (1)

where,

G = Gravitational Constant

ME = Mass of Earth

RE = Radius of Earth

g = Acceleration due to gravity on surface of earth = 9.8 ms²

When the person goes 2RE, distance above earth's surface. Then the total distance from center of earth becomes: 2RE + RE = 3RE.

Therefore, equation (1) becomes:

gh = (G)(ME)/(3RE)²

where,

gh = acceleration due to gravity at height

gh = (G)(ME)/(RE)²9

using equation (1), we get:

gh = g/9

Now, he weight is given by formula:

W = mg   ------- equation (2)

At height 2RE

Wh = (m)(gh)

where,

Wh = Weight at height = ?

m = mass of astronaut

Therefore, using vale of gh, we get:

Wh = mg/9

Using equation (2), we get:

<u>Wh = W/9</u>

6 0
3 years ago
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