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xz_007 [3.2K]
3 years ago
6

The value of 3' x10, when x = -2, can be

Mathematics
1 answer:
Westkost [7]3 years ago
7 0
I hope someone solves your problem :)
You might be interested in
Suppose f'(7)=9 and g(7)= 5. <br> Find h'(7) where h(x) = 3f(x) + 2g(x) + 7<br><br> h'(7)=???
Ratling [72]

Answer:

The value of h'(7) = 44 .

Step-by-step explanation:

Given:

f'(7)=9 and g(7)= 5

We have to find : h'(7)

Also,

⇔ h(x) = 3f(x) + 2g(x) + 7   ...equation (i)

Plugging the value of 'x' = 7 in equation (i) the equation can be re-framed as:

⇔ h(7) = 3f(7) + 2g(7) + 7

⇔ h(7) = 3f(7) + 2g(7) + 7

Now plugging the value of f'=(7)=9 and g(7)=5 in the above equation:

⇔ h(7) = 3(9) + 2(5) + 7

⇔ h(7)=27+10+7

⇔ h(7)=44

So the value of h=(7) = 44 .

6 0
4 years ago
1.7(10^−13)(3.5)(10^25)​
liq [111]

\boxed{\bf\huge{Answer:—}}

\sf \longmapsto5.95 \times  {10}^{ 12}

\boxed{\huge\bf{ Solution:—}}

\sf \longmapsto \: (1.7 \times 10  {}^{ - 13} )(3.5 \times  {10}^{25} )

\sf \longmapsto1.7 \times 3.5 ( {10}^{25}   \times  {10}^{ - 13} )

\sf \longmapsto \: 1.7 \times 3.5( {10}^{25 - 13} )

\sf \longmapsto3.5 \:  \times 1.7( {10}^{12} )

\sf \longmapsto5.95 \times  {10}^{ + 12}

4 0
3 years ago
Read 2 more answers
Evaluate h(x)=-2x+9 when x=-2,0, and 5 .<br><br> h(-2)= <br><br> h(0)=<br><br> h(5)=
gizmo_the_mogwai [7]

Step-by-step explanation:

Substitute the value in the parentheses into x.

<u>When x = -2</u><u>;</u>

h( - 2) =  - 2( - 2) + 9

h( - 2) = 4 + 9

h(  - 2) = 13

<u>When x = 0</u><u>;</u>

h(0) =  - 2(0) + 9

h(0) = 0 +9

h(0) = 9

<u>When x = 5:</u>

h(5) =  - 2(5) + 9

h(5) =  - 10 + 9

h(5) =  - 1

8 0
2 years ago
1. A card is picked at random from a pack of 52 playing cards. The probability that it is a 6 is?
salantis [7]

Answer:

1.) A - 5/52

2.) B - 4/9

3 0
3 years ago
Read 2 more answers
The digit in the hundreds place is neither prime nor composite.  The digit in the ones place is twice the digit in the hundreds
Levart [38]

Step-by-step explanation:

The only digit that is neither composite nor prime is 1, so the hundreds place is 1. Therefore, the digit in the ones place is twice 1, or 2. The only even prime number is 2, so the digit in the lakhs place is 2. We have 2 options for the tens thousands and tens places, 3 and 1 or 5 and 3 respectively. 7 and 5 does not work because 7 + 5 = 12, and 12 is not a digit. From this, the thousands place could be 4 or 8. Therefore, the number could be 234112 or 258132. Hope this helps!

5 0
3 years ago
Read 2 more answers
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