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3 years ago

The value of 3' x10, when x = -2, can be

Mathematics

1 answer:

Westkost [7]3 years ago

7 0

I hope someone solves your problem :)

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Suppose 12% of students surveyed said they have tried riding a zip line.

Arisa [49]

Answer:

12.

12% of 100= 12.

6 0

3 years ago

An airplane flies at an altitude of 28,500 feet. A submarine dives to a depth of 900 feet below sea level. What is the differenc

weeeeeb [17]

29,400

Mark brainliest please

Hope this helps you

3 0

3 years ago

A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill. You blindly reach into the

zubka84 [21]

Answer: $7.70

Step-by-step explanation:

Given : A box contains eighteen $1 bills, ten $5 bills, eight $10 bills, three $20 bills, and one $100 bill.

Total bills = $18+10+8+3+1=40$

We know that probability of any event = $\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

i.e. the probability of getting $1 bills = $P(E_1)=\dfrac{18}{40}=0.45$

Probability of getting $10 bills = $P(E_2)=\dfrac{10}{40}=0.25$

Probability of getting $5 bills = $P(E_3)=\dfrac{8}{40}=0.2$

Probability of getting $20 bills = $P(E_4)=\dfrac{3}{40}=0.075$

Probability of getting $100 bills = $P(E_5)=\dfrac{1}{40}=0.025$

$\text{Expected value =}1\times P(E_1)+5\times P(E_2)+10\times P(E_3)+20\times P(E_4)+100\times P(E_5)\\\\=1\times 0.45+5\times 0.25+10\times0.2+20\times 0.075+100\times 0.025\\\\=7.7$

Hence, the expected value of your draw= $7.70

5 0

4 years ago

A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2

alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0

4 years ago

Solve for x. The polygons in each pair are similar.

astraxan [27]

Answer:

higigj jo Dickenson g three-dimensional

4 0

3 years ago