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xz_007 [3.2K]
3 years ago
6

The value of 3' x10, when x = -2, can be

Mathematics
1 answer:
Westkost [7]3 years ago
7 0
I hope someone solves your problem :)
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Solve for m and n<br> I been stuck on this question for an hour
Crazy boy [7]

Answer:

m = 10 , n = 5\sqrt{2}

Step-by-step explanation:

using the cosine and tangent ratio in the right triangle and the exact values

cos45° = \frac{1}{\sqrt{2} } and tan45° = 1 , then

cos45° = \frac{adjacent}{hypotenuse} = \frac{5\sqrt{2} }{m} = \frac{1}{\sqrt{2} } ( cross- multiply )

m = 5\sqrt{2} × \sqrt{2} = 5 × 2 = 10

-----------------------------------------

tan45° = \frac{opposite}{adjacent} = \frac{n}{5\sqrt{2} } = 1 , then

n = 5\sqrt{2}

3 0
2 years ago
Solve the equations 11(x+10)=132
VladimirAG [237]
11(x+10) = 132

Distributive property

11x + 110 = 132

Now isolate the variable. 

11x + 110 = 132
        -110     -110

132 - 110 = 22

11x = 22

11x/11 = 22/11
x= 2

Answer:  x = 2

4 0
4 years ago
Read 2 more answers
The graph of y=x^2 was transformed to Y= -(x+3)^2 +5. Describe all transformations applied to the original function and determin
mina [271]

Hey there!

1. The graph was flipped vertically and now opens downward.

We know this because there is a negative sign in front of the equation:

y= \boxed- (x+3)^2+5

2. The graph was moved 3 units to the left.

We know this because there is 3 added to x inside of the parenthesis. Remember, inside (parenthesis) is opposite and acts on x, outside (parenthesis) is same and acts on y.

y=-(x\boxed{+3})^2+5

3. The graph was moved 5 units up.

We know this because there is 5 added at the end of the equation. It acts on y because it is outside of the parenthesis.

y=-(x+3)^2\boxed{+5}

Hope this helps!

3 0
3 years ago
I need help please it’s due tomorrow.......
Sholpan [36]
Let
x-------> the width of the rectangular area
y------> the length of the rectangular area

we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2

substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
 the length of the rectangular area is at most 45 ft

see the attached figure
the solution is<span> the shaded area</span>

4 0
3 years ago
Can someone help me!
victus00 [196]

Answer:

m∠A = 48.81°

Step-by-step explanation:

Given triangle is a right triangle and we have to measure ∠A.

Since, opposite side and adjacent sides of angle A has been given

So we will apply tangent rule to get the measure of angle A.

tan(∠A) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(∠A) = \frac{8}{7}

∠A = \text{tan}^{-1}(\frac{8}{7})

∠A = 48.814

  ≈ 48.81°

8 0
3 years ago
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