Answer:
The average rate of change as follows of I is -0.185.
Step-by-step explanation:
The relation between voltage V, current I, and resistance R in a circuit, according to the Ohm's law is:
It is provided that:
<em>V</em> = 20 V
The interval between which R varies is, R = 8 to R = 8.1.
Compute the value of I as follows:
Compute the average rate of change as follows of I as follows:
![=\frac{1}{0.1}[\frac{12}{8.1}-\frac{12}{8}]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B0.1%7D%5B%5Cfrac%7B12%7D%7B8.1%7D-%5Cfrac%7B12%7D%7B8%7D%5D)
![=\frac{12}{0.1}[\frac{8-8.1}{64.8}]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B12%7D%7B0.1%7D%5B%5Cfrac%7B8-8.1%7D%7B64.8%7D%5D)
Thus, the average rate of change as follows of I is -0.185.
So it will be
1/3(6)=-2/5(-5)
then will remove minus
1/3*6=2/5*5
then cancle 3 and 6 will be 2 and remove 5
So it become like this 2=2 it is True
Answer:
33.33%
Step-by-step explanation:
Given :
Breakup percentage = 15
New relationship percentage = 30
To obtain the steady state percentage of residents who are uninvolved, we could relate the scenario to the natural unemployment rate relation : seperation rate ÷ (seperation rate * finding rate)
Hence, we could use the Relation as this ;
Breakup percentage ÷ (Breakup percentage + new relationship rate)
15% ÷ (15% + 30%)
0.15 ÷ (0.15 + 0.30)
0.15 ÷ 0.45
= 0.33333
= 33.33%
Equation: 330-.255(5)=X. Multiply: .255(5)=1.275, 330-1.275=X. Subtract: 330-1.275=328.725 or 328.73 :)
To find that divide 32 by 40 and multiply by 100 so
32/40 *100% =80%
Therefore 32 is 80 percent of 40
