Benzene
- Benzene has low density than the water itself of about 0.9 g/cm³
Low denisty object than the water usually <u>floats on the water</u>.
Another example: orange peel which floats on water has density of about 0.84 g/cm³
A) Anode - hydrogen gas
Cathode-oxygen gas
B) Hydrogen gas - The gas burns with a pop sound
Oxygen gas - The gas rekindles a glowing splint
C) The volume of gas produced at the cathode is 23
<h3>What is electrolysis?</h3>
Electrolysis is the process by which electric current is passed through a substance to effect a chemical change.
The electrolysis of water produces two volumes of hydrogen at the anode and one volume of oxygen at the cathode.
The hydrogen gas burns with a pop sound. It is easily identified by this test. Also, oxygen is known to rekindle a glowing splint and this is a commonly used test for oxygen gas.
Since the ratio of hydrogen produced at the anode to oxygen produced at the cathode is 2:1 by volume; then when 23 of oxygen is produced at the cathode, 46 of hydrogen is produced at the anode.
Learn more about the electrolysis here:
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Answer:
2) 25.0mL aliquots of the solution in problem 1 are titrated with EDTA to the calmagite end point. A blank containing a small measured amount of Mg2+ requires 2.12mL of the EDTA to reach the end point. An aliquot to which the same amount of Mg2+ is added requires 25.88mL of the EDTA to reach the end point.
a. How many mL of EDTA are needed to titrate the Ca2+ ion in the aliquot?
b. How many moles of EDTA are there in the volume obtained in a.?
c. What is the molarity of the EDTA solution?
Explanation:
Given that;
Volume of aliquot = 25mL
Blank reading = 2.12mL
2a)
Volume of EDTA used for Ca²⁺ ion
25.88mL - 2.12mL = 23.76mL
Therefore mL of EDTA needed to titrate the Ca²⁺ ion in the aliquot is 23.76mL
2b)
Molarity of Ca²⁺ ion is 0.0172M
Mole of EDTA =
2c)
Molarity of EDTA = mole of EDTA / Vol. of EDTA
A substance that has a solubility of 12 grams/L of water would require 36/12 = 3 liters of water to dissolve 36 grams of the substance.