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mars1129 [50]
2 years ago
12

Based on the molecular structures of chloromethane and methane shown, a student makes the claim that a pure sample of chlorometh

ane has stronger intermolecular forces than a pure sample of methane has.
Chemistry
1 answer:
goblinko [34]2 years ago
7 0

Answer:

Yes, chloromethane has stronger intermolecular forces than a pure sample of methane has.

Explanation:

In both methane and chloromethane, there are weak dispersion forces. However, in methane, the dispersion forces are the only intermolecular forces present. Also, the lower molar mass of methane means that it has a lower degree of dispersion forces.

For chloromethane, there is in addition to dispersion forces, dipole-dipole interaction arising from the polar C-Cl bond in the molecule. Also the molar mass of chloromethane  is greater than that of methane implying a greater magnitude of dispersion forces in operation.

Therefore, chloromethane has stronger intermolecular forces than a pure sample of methane has.

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How can you tell if a compound contains a polyatomic ion because the entire compound has?
gayaneshka [121]
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3 years ago
What’s the ionic equation for lithium + water
disa [49]

Answer:

2Li(s) + 2H₂O(ℓ) ⟶ 2Li⁺(aq) + 2OH⁻(aq) + H₂(g)

Explanation:

An ionic equation uses the symbols (aq) [aqueous] to indicate molecules and ions that are soluble in water, (s) [solid] to indicate insoluble solids, and (ℓ) to indicate substances (usually water) in the liquid state.

In this reaction, solid lithium reacts with liquid water to form soluble lithium hydroxide and gaseous hydrogen .

1. Molecular equation

2Li(s) + 2H₂O(ℓ) ⟶ 2LiOH(aq) + H₂(g)

2. Ionic equation

Lithium hydroxide is a soluble ionic compound, so we write it as hydrated ions.

2Li(s) + 2H₂O(ℓ) ⟶ 2Li⁺(aq) + 2OH⁻(aq) + H₂(g)

7 0
3 years ago
How many grams of oxygen are required too burn 8.8g of c3h8?
hichkok12 [17]
From the balanced equation: 
<span>1mol C3H8 requires 5mol O2 for combustion </span>
<span>Molar mass C3H8 = 44g/mol </span>
<span>8.8g C3H8 = 8.8/44 = 0.2mol C3H8 </span>
<span>This will require 5*0.2 = 1.0mol O2 </span>
<span>Molar mass O2 = 32g/mol </span>
<span>Therefore 32g of O2 required.


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4 0
3 years ago
A compound has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen.
goldenfox [79]

The molecular formula of the compound that has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen is C2H6O2.

<h3>How to calculate molecular formula?</h3>

The molecular formula can be calculated from the empirical formula. The empirical formula of the compound is calculated as follows:

  • C = 38.7% = 38.7g
  • H = 9.76% = 9.76g
  • O = 51.5% = 51.5g

Next, we convert the mass to moles by dividing by their atomic mass:

  • C = 38.7 ÷ 12 = 3.23mol
  • H = 9.76 ÷ 1 = 9.76mol
  • O = 51.5÷ 16 = 3.22mol

Next, we divide by the smallest (3.22)

  • C = 1
  • H = 3
  • O = 1

Hence, the empirical formula of the compound is CH3O

If the molar mass of the compound is 62g/mol;

(CH3O)n = 62

31n = 62

n = 2

(CH3O)2 = C2H6O2

Therefore, the molecular formula of the compound that has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen is C2H6O2.

Learn more about molecular formula at: brainly.com/question/14425592

7 0
2 years ago
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