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mars1129 [50]
3 years ago
12

Based on the molecular structures of chloromethane and methane shown, a student makes the claim that a pure sample of chlorometh

ane has stronger intermolecular forces than a pure sample of methane has.
Chemistry
1 answer:
goblinko [34]3 years ago
7 0

Answer:

Yes, chloromethane has stronger intermolecular forces than a pure sample of methane has.

Explanation:

In both methane and chloromethane, there are weak dispersion forces. However, in methane, the dispersion forces are the only intermolecular forces present. Also, the lower molar mass of methane means that it has a lower degree of dispersion forces.

For chloromethane, there is in addition to dispersion forces, dipole-dipole interaction arising from the polar C-Cl bond in the molecule. Also the molar mass of chloromethane  is greater than that of methane implying a greater magnitude of dispersion forces in operation.

Therefore, chloromethane has stronger intermolecular forces than a pure sample of methane has.

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Which element must be present in an organic compound?(1) hydrogen (3) carbon(2) oxygen (4) nitrogen
White raven [17]
CARBON is the element that must be present in an organic compound. 
7 0
3 years ago
Read 2 more answers
A solution of NaOH has a concentration of 25.00% by mass. What mass of NaOH is present in 0.250 g of this solution? Use the peri
tekilochka [14]

Answer:

1) 0.0625  g.

2) 0.0125 g.

Explanation:

<em>1) A solution of NaOH has a concentration of 25.00% by mass. What mass of NaOH is present in 0.250 g of this solution?</em>

  • We can use the relation:

mass% of NaOH = [(mass of NaOH)/(mass of solution)] x 100.

mass% of NaOH = 25.0%, mass of NaOH = ???  g, mass of solution = 0.250 g.

∴ mass of NaOH = (mass% of NaOH)(mass of solution)/100 = (25.0%)(0.250 g)/100 = 0.0625  g.

<em>2) What mass of NaOH must be added to the solution to increase the concentration to 30.00% by mass?</em>

We can use the relation:

mass% of NaOH = [(mass of NaOH)/(mass of solution)] x 100.

mass% of NaOH = 30.0%, mass of NaOH = ???  g, mass of solution = 0.250 g.

∴ mass of NaOH = (mass% of NaOH)(mass of solution)/100 = (30.0%)(0.250 g)/100 = 0.075  g.

∴ The mass of NaOH should be added = 0.075 - 0.0625 = 0.0125 g.

9 0
4 years ago
Read 2 more answers
Consider the reaction between reactants s and o2: 2s(s)+3o2(g)→2so3(g)if a reaction vessel initially contains 7 mols and 9 mol o
nadya68 [22]

Answer: -

1 mol

Explanation: -

Number of moles of Sulphur S = 7

Number of moles of O2 = 9

The balanced chemical equation for the reaction is

2S (s)+3 O2 (g)→2SO3(g)

From the above reaction we can see that

3 mol of O2 react with 2 mol of S

9 mol of O2 will react with \frac{2 mol S x 9 mol O2}{3 mol O2}

= 6 mol of S

Unreacted S = 7 - = 1 mol.

If a reaction vessel initially contains 7 mol S and 9 mol O2

1 mole of s will be in the reaction vessel once the reactants have reacted as much as possible

6 0
4 years ago
Calculate the molarity of a 10.0% (by mass) aqueous solution of hydrochloric acid.
olga2289 [7]

The question is incomplete,the complete question :

Calculate the molality of a 10.0% (by mass) aqueous solution of hydrochloric acid:

a) 0.274 m

b) 2.74 m

c) 3.05 m

d) 4.33 m

e) the density of the solution is needed to solve the problem

Answer:

The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.

Explanation:

10.0% (by mass) aqueous solution of hydrochloric acid.

10 grams of HCl is present in 100 g of solution.

Mass of HCl = 10 g

Mass of solution = 100 g

Mass of solution = Mass of solute + Mass of water

Mass of water = 100 g - 10 g = 90 g

Moles of HCl = \frac{10 g}{36.5 g/mol}=0.2740 mol

Mass of water in kilograms = 0.090 kg

Molality = \frac{0.2740 mol}{0.090 kg}=3.05 mol/kg

The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.

6 0
3 years ago
Which transition metals are paramagnetic but can easily form ferromagnetic alloys with other metals?
Brrunno [24]

Answer: Paramagnetism is most easily observed in the salts of some of the first row transition metals (manganese through nickel). The se metal ions have unpaired electrons in degenerate d orbitals as predicted by Hund's rule and thus exhibit paramagnetism.

Explanation: METALS ARE ELECTRONS

AND PARAMAGNETIC OBSERVES SALT FORST ROWS ONLY

6 0
3 years ago
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