1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mars1129 [50]
2 years ago
12

Based on the molecular structures of chloromethane and methane shown, a student makes the claim that a pure sample of chlorometh

ane has stronger intermolecular forces than a pure sample of methane has.
Chemistry
1 answer:
goblinko [34]2 years ago
7 0

Answer:

Yes, chloromethane has stronger intermolecular forces than a pure sample of methane has.

Explanation:

In both methane and chloromethane, there are weak dispersion forces. However, in methane, the dispersion forces are the only intermolecular forces present. Also, the lower molar mass of methane means that it has a lower degree of dispersion forces.

For chloromethane, there is in addition to dispersion forces, dipole-dipole interaction arising from the polar C-Cl bond in the molecule. Also the molar mass of chloromethane  is greater than that of methane implying a greater magnitude of dispersion forces in operation.

Therefore, chloromethane has stronger intermolecular forces than a pure sample of methane has.

You might be interested in
The combined gas law states that
seropon [69]

Answer:

Option B. PV = nRT.

Explanation:

From the above,

C = PV / T. (1)

But, C is directly proportional to n, where R is the gas constant i.e

C & n

C = nR

Substituting the value of C into equation (1), we have:

C = PV / T

nR = PV / T

Cross multiply to express in linear form

nRT = PV

Therefore,

PV = nRT

8 0
3 years ago
(5.0 m3) ( 7.5 mmHg) = (P)(4.0m3)
anzhelika [568]

It looks like we are solving for a pressure.  All that is required is some algebraic manipulation to find our pressure in mmHg.

Given:

(5.0 m³)(7.5 mmHg) = (P)(4.0m³)

Multiply:

37.5 = 4.0P

Divide:

9.375 = P

P = 9.4 mmHg (remember sig figs)

<h3>Answer:</h3>

9.4 mmHg

7 0
3 years ago
Answer the following question for this equation: 2H2 + O2 → 2H2O
kondaur [170]

Answer:

B. 1:2

Explanation:

Molar ratio depicts the relationship between the number of moles of two substances. The chemical equation in this question is as follows:

2H2 + O2 → 2H2O

This question is asking to identify the molar ratio of O2 to H2O in the equation. Since 1 mole of oxygen gas (O2) produces 2 moles of water (H2O). Hence, the O2 to H2O molar ratio is 1:2.

6 0
2 years ago
Which of the following measurements has three significant figures?
Free_Kalibri [48]

The correct answer is <u>C: 0.510 m</u>

<u></u>

N I C E - D A Y!

8 0
2 years ago
Read 2 more answers
Which of the following is not the same as 2.97 milligrams? 0.0000297 kg, 0.00297 g, 0.297 ch
Travka [436]

the correct answer its  0.002975

4 0
3 years ago
Read 2 more answers
Other questions:
  • A new potential heart medicine, code-named X-281, is being tested by a pharmaceutical company, Pharma-pill. As a research techni
    13·1 answer
  • What are the uses of zinc
    12·2 answers
  • A cup of gold colored metal bed was measured to have a mask for 25 g. By water displacement, the volume of the bed was calculate
    13·1 answer
  • Why is chemistry important for the study of living things
    12·2 answers
  • 4720 kJ of energy are supplied to a material in order to raise its temperature by 65K. If the specific heat capacity of the mate
    11·1 answer
  • What is the mass in grams of 5.25 x 1024 molecules of NaOH?
    6·1 answer
  • An atom has the electron configuration of 1s22s22p5 how many electrons are in that atom
    11·1 answer
  • Which object has the greatest K.E.?"<br> top of a hill<br> bottom of a hill<br> middle of a hill
    9·2 answers
  • Can you always tell by looking at a substance if it is pure or not? ​
    10·1 answer
  • Please help, I don't know the formulas to do these and I'd like to know HOW y'all get the answers...thank you so much.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!