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3 years ago

Robert can type 360 words in 3 minutes. Jocelyn can type 525 words in 5 minutes.

Mathematics

1 answer:

abruzzese [7]3 years ago

6 0

Step-by-step explanation:

Robert: 360/ 6 = 62 words per minute

Jocelyn: 525/ 5= 58 words per minute

Jocelyn types faster. I haven't done 5th grade math in so long... lol if wrong please correct me..

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Answer:

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Step-by-step explanation:

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2 years ago

Help with this question

Sholpan [36]

With some simplification,

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2 years ago

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a

kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented $h(t)=-16t^2+20t$ .

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?

We will use average rate of change formula to solve our given problem.

$\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}$

$\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{6}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{2\cdot 6}{1}$

$\text{Average rate of change}=12$

Therefore, Spot's average rate of ascent is 12 feet per second.

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3 years ago

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2 years ago

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Igoryamba

Answer:

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Step-by-step explanation:

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