<span>(f+g)(x) ≥ 3 for all values of x</span>
Therefore 
Step-by-step explanation:
Given,





Therefore 
Answer: You will need 3.5lbs of the cheaper candy
and 5 lbs of the expensive candy.
Step-by-step explanation:
Let x represent the number of pounds of the cheaper candy that you would need.
Let y represent the number of pounds of the expensive candy that you would need.
You would like to have 8.5 lbs of a candy mixture. It means that
x + y = 8.5
You have one type of candy that sells for $1.70/lb and another type of candy that sells for $3.40/lb. The candy mixture would sell for $2.70/lb. It means that the total cost of the mixture would be 8.5 × 2.7 = $22.95. The expression would be
1.7x + 3.4y = 22.95- - - - - - - - - - - 1
Substituting x = 8.5 - y into equation 1, it becomes
1.7(8.5 - y) + 3.4y = 22.95
14.45 - 1.7y + 3.4y = 22.95
- 1.7y + 3.4y = 22.95 - 14.45
1.7y = 8.5
y = 8.5/1.7
y = 5
x = 8.5 - y = 8.5 - 5
x = 3.5
Using the future value formula, it is found that you would need to deposit $272.95 in the account each month.
<h3>What is the future value formula?</h3>
It is given by:
![V(n) = P\left[\frac{(1 + r)^{n-1}}{r}\right]](https://tex.z-dn.net/?f=V%28n%29%20%3D%20P%5Cleft%5B%5Cfrac%7B%281%20%2B%20r%29%5E%7Bn-1%7D%7D%7Br%7D%5Cright%5D)
In which:
- n is the number of payments.
For this problem, considering that there are monthly compoundings, the parameters are:
r = 0.08/12 = 0.0067, V(n) = 300000, n = 25 x 12 = 300.
Hence we solve for P to find the monthly payment.
![V(n) = P\left[\frac{(1 + r)^{n-1}}{r}\right]](https://tex.z-dn.net/?f=V%28n%29%20%3D%20P%5Cleft%5B%5Cfrac%7B%281%20%2B%20r%29%5E%7Bn-1%7D%7D%7Br%7D%5Cright%5D)
![300000 = P\left[\frac{(1.0067)^{299}}{0.0067}\right]](https://tex.z-dn.net/?f=300000%20%3D%20P%5Cleft%5B%5Cfrac%7B%281.0067%29%5E%7B299%7D%7D%7B0.0067%7D%5Cright%5D)
1099.12P = 300000
P = 300000/1099.12
P = $272.95.
You would need to deposit $272.95 in the account each month.
More can be learned about the future value formula at brainly.com/question/24703884
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D. If you are working hard, then you will get good grades.