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2 years ago

Plzz help if right i give brainliest

Mathematics

1 answer:

bija089 [108]2 years ago

6 0

Answer:

b. (x+6)(x-6)

Step-by-step explanation:

x^2-36 So to get to this answer you can do two things

1. Guess and check

2. Factor it out (which is what I like to do)

In order to get x^2 you need 2xs that are positive which knocks out c and d

Then to get to -36, you need to multiply a positive 6 and a negative 6

(This was poorly explained but if you need anymore help just lmk)

You might be interested in

How do you calculate 278 × 11 using estimation?

neonofarm [45]

Answer:

2800

Step-by-step explanation:

round 278 to 280

then round 11 to 10

then times the 2 answers together

8 0

2 years ago

Read 2 more answers

(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3) Enter the answer in science notification

Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

$(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})$

The numeric part simply yields

$3.8\times2.37 = 9.006$

As for the powers of 10, you have to add the exponents, using the rule

$a^b \times a^c = a^{b+c}$

So, we have

$10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}$

So, the final answer is

$9.006\times 10^{-9}$

7 0

2 years ago

A town's population has been growing linearly. In 2003 the population was 47,000. The population has been growing by 1200 people

blsea [12.9K]

Answer:

Step-by-step explanation:

The population in 2003= 47000

Since the population increase by 1200 every year,

in 2004 the population will be 47000+1200

in 2005 the population will be 47000+(1200+1200) which is the same as

47000+2(1200) where 2 is 2 years after 2003,

Therefore the population x years after 2003 is 47000+x(1200).

P= 47000+1200x

b) The population at 2009 which is 6 years after 2003 will be

47000+(1200)*6=47000+7200= 54200

The population at 2009 is 54200,

7 0

2 years ago

A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3>Given :-</h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

We have to find the distance between the golf ball and the center of the green .

<h3>Let's Begin :-</h3>

Let assume that the distance between the golf ball and central of green is x

Here, 

Distance between marker and centre of green is 150 yards
That is, Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
That is, Angle = 100°
The golfer peces off 30 yards to his ball
That is, Base = 30 yards

According to the law of cosine :-

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

So, For Hypotenuse law of cosine will be :-

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

Subsitute the required values,

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0

2 years ago

Math: Please help me. I don’t understand. Thank you for your time.

GuDViN [60]

I Believe it’s 1,890

7 0

3 years ago