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3 years ago

Which is hotter, Canopus or Vega? How much brighter?

1 answer:

4 0

Temperature determines the hotness or coldness. The surface temperature of Canopus is 7350 K. The surface temperature of Vega is 9602 K. Because the surface temperature of Vega is greater than Canopus, Vega is hotter.

Brightness is determined by the star's magnitude. The apparent magnitude of Canopus is (-0.72) and that of Vega is (0.03). we know that, lesser the magnitude, brighter is the star. Hence, Canopus is brighter.

Vega is hotter but Canopus is brighter. This is because, brightness depends on the star's distance and size of the star as well other than the factor temperature.

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What are important things about mental health

Paul [167]

Answer:

Mental health includes our emotional, psychological, and social well-being. It affects how we think, feel, and act. It also helps determine how we handle stress, relate to others, and make healthy choices. Mental health is important at every stage of life, from childhood and adolescence through adulthood

Explanation:

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3 years ago

Read 2 more answers

A child of mass 27 kg swings at the end of an elastic cord. At the bottom of the swing, the child's velocity is horizontal, and

snow_tiger [21]

Answer:

The magnitude of the rate of change of the child's momentum is 794.11 N.

Explanation:

Given that,

Mass of child = 27 kg

Speed of child in horizontal = 10 m/s

Length = 3.40 m

There is a rate of change of the perpendicular component of momentum.

Centripetal force acts always towards the center.

We need to calculate the magnitude of the rate of change of the child's momentum

Using formula of momentum

$\dfrac{dp}{dt}=F$

$\dfrac{dP}{dt}=\dfrac{mv^2}{r}$

Put the value into the formula

$\dfrac{dP}{dt}=\dfrac{27\times10^2}{3.40}$

$\dfrac{dP}{dt}=794.11\ N$

Hence, The magnitude of the rate of change of the child's momentum is 794.11 N.

7 0

3 years ago

☆Will Give Brainliest☆

Masja [62]

Answer: :)

1.) The Doppler effect is, the change in sound or light that occurs whenever there is motion between the source and its observer. The siren of the fire engine has a lower pitch as it moves away because the waves are now spread out causing a lower frequency and a lower pitch.

2.) Wave frequency is related to wave energy. Since all that waves really are is traveling energy, the more energy in a wave, the higher its frequency. The lower the frequency is, the less energy in the wave.

5 0

3 years ago

The hydraulic oil in a car lift has a density of 8.30 102 kg/m³. The weight of the input piston is negligible. The radii of the

denpristay [2]

Answer:

(a) $F_i=68.58\ N$

(b) $F_i=69.903\ N$

Explanation:

Given:

density of hydraulic oil, $\rho=830\ kg.m^{-3}$

radius of input piston, $r_i=6.3\times 10^{-3}\ m$

radius of output plunger, $r_o=0.125\ m$

force to be supported, $F_o=27000\ N$

(a)

Condition:The bottom surfaces of piston and plunger at the same level.

According to Pascal's law the pressure of a fluid is exerted equally in all directions against the walls of its container.

Mathematically:

$\frac{F_i}{A_i} =\frac{F_o}{A_o}$

putting respective values

$\frac{F_i}{\pi\times r_i^2} =\frac{27000}{\pi\times r_o^2}$

$\frac{F_i}{\pi\times (6.3\times 10^{-3})^2} =\frac{27000}{\pi\times 0.125^2}$

$F_i=68.58\ N$

(b)

Condition:The bottom surface of the output plunger is 1.30 m above that of the input piston.

Given:

$h=1.3\ m$

Now,

$P_i=P_o+\rho.g.h$

$\frac{F_i}{\pi\times (6.3\times 10^{-3})^2} =\frac{27000}{\pi\times 0.125^2} +830\times 9.8\times 1.3$

$F_i=69.903\ N$

7 0

3 years ago

A duck swimming on the surface of a pond has an

Gemiola [76]

From the given information:

Taking the movement of the Duck in the North as the x-direction
The movement of the Duck in the East direction as the y-direction

However, we will have to compute the initial velocity and the acceleration of the duck in their vector forms.

<h3>In vector form;</h3>

The initial velocity is:

$\mathbf{u ^{\to} = 0.7 m/s ( -cos 25^0 \hat x + sin 25^0 \hat y ) \ m/s}$

The acceleration is:

$\mathbf{a ^{\to} = 0.5 m/s ( cos 41^0 \hat x - sin 41^0 \hat y ) \ m/s^2}$

The objective of this question is to determine the speed of the duck at a certain time. Since it is not given, let's assume we are to determine the Duck speed after 4 seconds of accelerating;

Then, it implies that time (t) = 4 seconds.

Using the first equation of motion:

$v^{\to} = u ^{\to} + a^{\to} t$

Then, we can replace their values into the equation of motion in order to determine the speed:

$\mathbf{v^{\to} =\Big(0.7 ( -cos 25^0 \hat x + sin 25^0 \hat y )+4 \times 0.5 ( cos 41^0 \hat x - sin 41^0 \hat y )\Big)}$

$\mathbf{v^{\to} =\Big(0.7 ( -cos 25^0 \hat x + sin 25^0 \hat y )+2.0 ( cos 41^0 \hat x - sin 41^0 \hat y )\Big)}$

$\mathbf{v^{\to} =\Big( ( -0.7 cos 25^0 \hat x + 0.7 sin 25^0 \hat y )+( 2.0cos 41^0 \hat x - 2.0sin 41^0 \hat y )\Big)}$

Collect like terms:

$\mathbf{v^{\to} =\Big( (2.0cos 41^0 -0.7 cos 25^0 )\hat x+( 0.7 sin 25^0 - 2.0sin 41^0 )\Big)\hat y}$

$\mathbf{v^{\to} =0.87500 \hat x- 1.01629 \hat y}$

Thus, the magnitude is:

$\mathbf{v^{\to} =\sqrt{(0.87500 )^2 +( 1.01629 )^2}}$

$\mathbf{v^{\to} =\sqrt{0.76563 +1.03285}}$

$\mathbf{v^{\to} =\sqrt{1.79848}}$

$\mathbf{v^{\to} =1.34 \ m/s}$

Therefore, we can conclude that the speed of the duck after 4 seconds is 1.34 m/s

Learn more about vectors here:

brainly.com/question/17108011?referrer=searchResults

4 0

3 years ago