#78
Airplane start with initial speed
now the takeoff velocity is given as
acceelration is given as
now we have
from above equation we have
#79
Airplane start with initial speed
now the takeoff velocity is given as
acceelration is given as
now we have
from above equation we have
Answer:
120 m/s if m/s means miles per second than
Explanation:
15 × 8
Answer: set up a reminder so you won't forget also try clearing your schedule so you can have more time
<span>To do this question, we need to know that momentum is conserved, meaning the overall velocity of the two balls has to be the same before and after the collision. </span>
<span>After collision... </span>
<span>Ball 1: 4.33m/s *cos 30 = 3.75 m/s (x-component) </span>
<span>4.33m/s * sin 30 = 2.165 m/s ( y-component) </span>
<span>Ball 2 (struck ball): 5 m/s - 3.75m/s = 1.25 m/s (x-component) </span>
<span>-2.165 m/s (y-component) note: it has to be in the opposite direction to conserve momentum </span>
<span>tan-1(2.165/1.25) = 60 degrees </span>
<span>Struck ball's velocity = sqrt(1.25^2 + 2.165^2) = 2.5 m/s at 60 degree with respect to the original line of motion. </span>
<span>Hope you understand!</span>
