(x + y)² and z² + 4(1/2 xy) both represent the area of the outer square and are equal.
Step-by-step explanation:
- Step 1: The below reasons explain why the expression is a true equation.
1. The expression (x + y)² finds the area of the outer square by squaring its side length.
[In the figure, side length of the outer square = x + y and area of a square = (side length)²]
2. The expression z² + 4(1/2 xy) finds the area of the outer square by adding the area of the inner square and the four triangles.
[In the figure the length of the inner square is z, the triangles have a base x and height y and area of a triangle = 1/2 base × height]
⇒ So the left hand side and right hand side of the expression is equal.
Answer: 13b + 43
You want to substitute the value of the variable into the equation and simplify it. When doing this, the answer is 13b + 43.
Step-by-step explanation:
Hope this helps =)
Answer: she biked 0.8 hour each day
Step-by-step explanation:
Let x represent the number of hours that she jogged on both days.
Let y represent the number of hours that she biked on both days.
Distance = speed × time
On the first day, she jogs at a rate of 6 miles/hour and bikes at a rate of 10 miles/hour. She covers a total of 26 miles that day. This is expressed as
6x + 10y = 26- - - - - - - - - - - - - - - 1
The second day, she continues to jog at a rate of 6 miles/hour, but a hamstring pull slows her biking rate to 5 miles/hour. The second day she covers a total of 22 miles. This means that
6x + 5y = 22- - - - - - - - - - - -2
Subtracting equation 2 from equation 1, it becomes
5y = 4
y = 4/5 = 0.8
Substituting y = 0.8 into equation 1, it becomes
6x + 10(0.8) = 26
6x + 8 = 26
6x = 26 - 8 = 18
x = 18/6
x = 3
His usual straight-time pay is $603.327375 per week
<h3>How to determine his usual straight-time pay?</h3>
The given parameters are
Rate = $16.655 per hour
Duration = 36.225 hours per week
His usual straight-time pay is calculated as
Usual pay = Rate * Duration
So, we have
Usual pay = $16.655 per hour * 36.225 hours per week
Evaluate the product
Usual pay = $603.327375 per week
Hence, his usual straight-time pay is $603.327375 per week
Read more about linear rates at
brainly.com/question/7040405
#SPJ1
