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masya89 [10]
3 years ago
12

Is aloe vera a living or non-living thing?

Chemistry
1 answer:
Afina-wow [57]3 years ago
3 0

Answer:

It is a living plant

Explanation:

You might be interested in
H3C6H507 + H2O + H3O+ + H2C6H507<br> acid <br> base
Aleonysh [2.5K]

Explanation:

an acid will give away a proton and become a conjugate base.

A base will accept a proton and become a conjugate acid.

3 0
3 years ago
A decomposition reaction, with a rate that is observed to slow down as the reaction proceeds, has a half-life that does not depe
mr_godi [17]

Answer: A plot of the natural log of the concentration of the reactant as a function of time is linear.

Explanation:

Since it was explicitly stated in the question that the half life is independent of the initial concentration of the reactant then the third option must necessarily be false. Also, the plot of the natural logarithm of the concentration of reactant against time for a first order reaction is linear. In a first order reaction, the half life is independent of the initial concentration of the reactant. Hence the answer.

3 0
4 years ago
A clear, pure liquid sample is brought into the lab and exposed to an electrical current. Different gases are produced on each o
aleksklad [387]
It would be a compound.
4 0
3 years ago
you find that 7.36g of a compound has decomposed to give 6.93g of oxygen. the only other element in the compound is hydrogen. if
slavikrds [6]
First solve the moles of oxgen present in the compound

mol O = 6.93 g O ( 1 mol O / 16 g O )
mol O = 0.43 mol H

then solve the moles of hydrogen present
mol H = ( 7.36 - 6.93) g H ( 1 mol H / 1 g H)
mol H = 0.43 mol H
so the O and H are in the same mole content so the molecular formula would be OH, but the molar mass will not satisfy. so the answer would be
H2O2

8 0
3 years ago
Read 2 more answers
A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature
Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

  • v_0=500
  • \alpha =1.12\times 10^{-4}
  • \Delta \epsilon = 25

Now,

Increase in volume will be:

⇒ \Delta V = \alpha\times v_0\times \Delta \epsilon

By putting the given values, we get

           =1.12\times 10^{-4}\times 500\times 25

           =1.12\times 10^{-4}\times 12500

           =1.4  \ mL

8 0
3 years ago
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