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3 years ago

What can be found in the Asteroid Belt?

Chemistry

1 answer:

Akimi4 [234]3 years ago

5 0

Answer:

astrioids can be found at the astrioid belt

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The molecule ch3-ch2-ch2-ch2-ch2-ch2-ch3 is best described as a(n) ________.

Gwar [14]

Given molecule:

CH3-CH2-CH2-CH2-CH2-CH2-CH3

- The molecule contain only C and H atoms, hence it is a hydrocarbon

- The C atoms in the linear chain are linked together by carbon-carbon single bonds, hence it is a saturated compound

- It has 7 C atoms and 16 H atoms, hence the molecular formula is C7H16

-The molecular formula can be generally represented as CnH2n+2 where n = 7. This corresponds to the general molecular formula for alkanes

The given molecule is best described as an <u>alkane</u>

7 0

3 years ago

Carbon-12 contains 6 protons and 6 neutrons. The radius of the nucleus is approximately 2.7 fm (femtometers) and the radius of t

Slav-nsk [51]

Explanation:

Let us assume that volumes is equal to spheres volume of nucleus.

fm = femto meter = $10^{-15}$

pm = pico meter = $10^{-12}$

Hence, calculate the volume as follows.

V = $\frac{4}{3} \times \pi \times r^{3}$

= $\frac{4}{3} \times 3.14 \times (2.7)^{3}$

= 82.4481 $fm^{3}$ (cubic femtometers)

or, = 82 $fm^{3}$

Now, we will calculate the volume of the atom as follows.

V = $\frac{4}{3} \times \pi \times r^{3}$

= $\frac{4}{3} \times 3.14 \times (70)^{3}$

= 1436758.4 $pm^{3}$ (cubic picometers)

thus, we can conclude that volume of the nucleus is 82 $fm^{3}$ and volume of the atom is 1436758.4 $pm^{3}$ .

7 0

3 years ago

How many atoms of each element are in one molecule of this product.

anastassius [24]

I assume about 5 atoms are in one molecule of this product

7 0

3 years ago

en un recipiente se tiene 800 g de una solución al 35% en masa de ácido sulfuroso, de la cual se evapora 80ml de agua. ¿cuál es

Alinara [238K]

The mass percent of sulfurous acid in the new solution : 38.9%

<h3>Further explanation</h3>

<em>In a container you have 800 g of a 35% by mass solution of sulfurous acid, from which 80 ml of water evaporates. What is the mass percent of sulfurous acid in the new solution? data: density of water is 1g / ml.</em>

<em />

solution 1

composition :

35% acid :

$\tt 0.35\times 800~g=280~g$

water :

$\tt 800-280=520~g$

solution 2(new solution)

composition :

water

$\tt 520-(80~ml\times 1~g/ml)=440~g$

Total mass of new solution after water evaporated

$\tt 280(acid)+440(water)=720~g$

%mass of acid in a new solution

$\tt \dfrac{280}{720}\times 100\%=38.9\%$

5 0

2 years ago

If a sample is thought to be several million years old, which method would best help to determine its absolute age?

Makovka662 [10]

The answer is B)Ar-40/k-40

6 0

3 years ago