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ollegr [7]
3 years ago
12

What can be found in the Asteroid Belt?

Chemistry
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

astrioids can be found at the astrioid belt

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Within the water cycles, where do individual water molecules reside the longest?
solniwko [45]
Condensation and precipitation
4 0
4 years ago
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The first IE of neon (atomic number 10) is significantly higher than that of argon (atomic number 18) but significantly
lbvjy [14]

Explanation:

Different atoms binds their outermost shell electrons with different amount of energy.

The amount of energy required to remove an electron from an atom is the ionization energy.

  • Ionization energy measures the readiness of an atom to lose electrons.
  • From the given problem, we can infer that in group O the ionization energy decreases down the group.
  • Helium has the highest ionization energy.
  • Down a group on the periodic table, ionization energy decrease because:
  1.  atomic radii increases down the group.
  2. there is an increasing shielding/screening effect of inner shell electrons on the outermost shell electrons.

Learn more:

Ionization energy brainly.com/question/2153804

#learnwithBrainly

8 0
3 years ago
What is the total ionic equation for cuso4+2naoh>>cu(oh)2+na2so4
iVinArrow [24]

Answer:

CuSO4 + 2 NaOH = Cu(OH)2 + Na2SO4

3 0
3 years ago
Question 8 of 8> 0 Attempt 2 A chemist needs to determine the concentration of a sulfuric acid solution by titration with a s
Nesterboy [21]

Answer:

12.29 M

Explanation:

  • The reaction that takes place is:

H₂SO₄ + 2NaOH → 2Na⁺ + SO₄⁻² + 2H₂O

  • Now let's calculate the <u>moles of H₂SO₄ that were titrated</u>:

0.1284 M * 0.1915L*\frac{1molAcid}{2molNaOH} = 0.01229 mol H₂SO₄.

  • Thus, the <u>concentration of the diluted solution is</u>:

0.01229 mol H₂SO₄ / 0.010 L = 1.229 M

  • Finally, the <u>concentration of the original acid solution is:</u>

1.229 M*\frac{250mL}{25mL} = 12.29 M

5 0
3 years ago
A drop of water with a mass of 0.48 g is vaporized at 100 ∘C and condenses on the surface of a 55- g block of aluminum that is i
bagirrra123 [75]

The final temperature in Celsius of the metal block is 49°C.

<h3>How to find the number of moles ?</h3>

Moles water = \frac{\text{Given mass}}{\text{Molar Mass}}

                     = \frac{0.48\ g}{18\ \text{g/mol}}

                     = 0.0266 moles  

                   

Heat lost by water = 0.0266 mol x 44.0 kJ/mol

                                = 1.17 kJ

                                = 1170 J           [1 kJ = 1000 J]

Heat lost = Heat gained

Heat gained by aluminum = 1170 J  

1170 = 55 x 0.903 (T - 25) = 49.7 T - 1242  

1170 + 1242 = 49.7 T  

T = 48.5°C (49°C at two significant figures)

Thus from the above conclusion we can say that The final temperature in Celsius of the metal block is 49°C.

Learn more about the Moles here: brainly.com/question/15356425

#SPJ1

7 0
2 years ago
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