Answer:
Hello my Friend! The answer is: Manganese(III) oxide is a transition metal compound. The oxidation state of manganese in this compound is +3 , and the chemical formula of the compound is Mn2O3.
Explanation:
Manganese can have two oxidation states: +2 and +3, but in this case, the "(III)" indicates that in this compound, the state of oxidation is +3.
Answer:
(a) oxygen
(b) 154g (to 3sf)
(c) 79.9% (to 3sf)
Explanation:
mass (g) = moles × Mr/Ar
note: eqn means chemical equation
(a)
moles of P = 84.1 ÷ 30.973 = 2.7152 moles
moles of O2 = 85÷2(16) = 2.65625 moles
Assuming all the moles of P is used up,
moles of O2 / moles of phosphorus = 5/4 (according to balanced chemical eqn)
moles of O2 required = 5/4 × 2.7152moles = 3.394 moles (more than supplied which is 2.65625moles)
therefore there is insufficient moles of O2 and the limiting reactant is oxygen.
(b)
moles of P2O5 produced
= 2/5 (according to eqn) × 2.7152
= 1.08608moles
mass of P2O5 produced
= 1.08608 × [ 2(30.973) + 5(16) ]
= 154.164g
= approx. 154g to 3 sig. fig.
(c)
% yield = actual/theoretical yield × 100%
= 123/154 × 100%
= 79.870%
= approx. 79.9% (to 3sf)
Answer:
16L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 4L
P1 (initial pressure) = 4atm
P2 (final pressure) = 1atm
V2 (final volume) =?
Using Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:
P1V1 = P2V2
4 x 4 = 1 x V2
16 = V2
V2 = 16L
Therefore, her new lungs volume is 16L
Endpoint . this is when the color of the indicator changes while equivalence is when added titrant is chemically equivalent completely to the analyte sample
<h2>Answer :-</h2>
<h3>Iodine has 53 protons and 53 electrons (because it has no charge the number of protons equals the number of electrons). Iodine-131 has 131 protons and neutrons.</h3>
