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3 years ago

1. A dry, empty bottle is placed in an ice bath. After the air inside the bottle is cooled off, a balloon is placed

Chemistry

2 answers:

Alex777 [14]3 years ago

8 0

Answer:

hot air rises and expanded the balloon

Explanation:

thats it.

ser-zykov [4K]3 years ago

6 0

The hot air rises and expanded the ballon. This is as the air in the bottle cools down, the molecules of the air slow down and take up less space because they move closer together. The air then moves out of the balloon and back into the bottle, causing the balloon to deflate.

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a paint company ants totest wether a new additive will make thier paint resist fading. Which test would include andan acceptable

luda_lava [24]

There are a few ways to do this. The best way I can think of is to start out the paint with no additives and have that as a control. You can test that on whatever your painting or do it in a lab with heat lamps and lights if that is a possible option. However you decide to do the testing, after starting with the control test, add different additives and see which ones fades less the original without any additives. This is the best scenario for a simple yet informative test.

Hope that helps!

6 0

4 years ago

How to overcome overshot in tritation

spayn [35]

Answer:

The method involves students exhaling air using a plastic straw into the over-titrated acid-base mixture, which turned pink-colored with phenolphthalein indicator.

7 0

3 years ago

A movable piston traps 0.205 moles of an ideal gas in a vertical cylinder. If the piston slides without friction in the cylinder

Mazyrski [523]

Answer : The work done on the gas will be, 418.4 J

Explanation :

First we have to calculate the volume at 270°C.

$PV_1=nRT$

where,

P = pressure of gas = 1 atm

$V_1$ = volume of gas = ?

T = temperature of gas = $270^oC=273+270=543K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_1=0.205mol\times 0.0821L.atm/mol.K\times 543K$

$V_1=9.12L$

Now we have to calculate the volume at 24°C.

$PV_2=nRT$

where,

P = pressure of gas = 1 atm

$V_2$ = volume of gas = ?

T = temperature of gas = $24^oC=273+24=297K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_2=0.205mol\times 0.0821L.atm/mol.K\times 297K$

$V_2=4.99L$

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 9.12 L

$V_2$ = final volume = 4.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (4.99-9.12)L$

$w=4.13L.artm=4.13\times 101.3J=418.4J$

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas will be, 418.4 J

6 0

3 years ago

How many molecules are in 20.0 L(liters) of SO2 at STP

Finger [1]

5.4 x 10²³ molecules

Explanation:

Given parameter

Volume of gas = 20L

Condition of reaction = STP

Unknown:

number of molecules

Solution:

The number of molecules of a substance is given by;

Number of molecules = Number of moles x avogadro's constant

Number of moles at stp = $\frac{volume of gas}{22.4}$

Number of moles of SO₂ = $\frac{20}{22.4}$ = 0.893mole

Number of molecules = 0.893 x 6.02 x 10²³ = 5.4 x 10²³ molecules

learn more:

Number of molecules brainly.com/question/10818009

#learnwithBrainly

4 0

3 years ago

How much energy in Joules, does 80 (g) grams of water at an initial temperature of 40°C need to absorb to have its temperature r

Zinaida [17]

Answer:

Q = 6688 J

Explanation:

Given data:

Energy absorbed = ?

Mass of water = 80 g

Initial temperature = 40°C

Final temperature = 60°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

specific heat capacity of water 4.18 j/g.°C

ΔT = 60°C - 40°C

ΔT = 20°C

Q = 80 g ×4.18 j/g.°C × 20°C

Q = 6688 J

4 0

3 years ago

Read 2 more answers