2 years ago

Which equation represents neutralization?

Chemistry

1 answer:

earnstyle [38]2 years ago

6 0

Answer:

3) 2KOH(aq) + H2SO4(aq) ⇒ K2SO4(aq) + 2H2O(l)

Explanation:

KOH is a strong base and a H2SO4 is a strong acid. The two react in a neutralization reaction, producing a salt and water.

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A solution is prepared at that is initially in benzoic acid , a weak acid with , and in sodium benzoate . Calculate the pH of th

Kisachek [45]

Answer:

$pH=4.1$

Explanation:

Hello,

In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:

$pH=pKa+log(\frac{[base]}{[acid]} )$

Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:

$pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1$

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2 years ago

chemist is using 387 mL of solution of acid in water if 13.3 of the solution is acid how many milliliters of acid are there roun

Greeley [361]

Answer:

V acid = 51.471 mL

Explanation:

%v/v = [(compoud volumen)/(solution volume)]×100

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