Answer:
bromine is more reactive non-metal.
Explanation:
Both the elements have to gain 1 electron but the size of bromine is less than the size of astatine. And therefore, the tendency of accepting an electron by bromine is more than the tendency of astatine. Hence, bromine is more reactive non-metal.
Answer:
0.01744 M is the hardness of the groundwater.
1,744 ppm is the hardness of the groundwater in parts per million of calcium carbonate by mass.
Explanation:

In = Indicator
Concentration of calcium ion in groud water = 
Volume of ground water = 
Concentration of EDTA solution = 
Volume of EDTA solution = 



![[CaCO_3]=[Ca^{2+}]](https://tex.z-dn.net/?f=%5BCaCO_3%5D%3D%5BCa%5E%7B2%2B%7D%5D)
So. ![[CaCO_3]=0.01744 M](https://tex.z-dn.net/?f=%5BCaCO_3%5D%3D0.01744%20M)
0.01744 M is the hardness of the groundwater.
0.01744 Moles of calcium carbonate are present in 1 Liter of solution.
Mass of 0.01744 moles of calcium carbonate =

1 g = 1000 g
1.744 g = 1.744 × 1000 mg = 1,744 mg

The hardness of the groundwater in parts per million :

1,744 ppm is the hardness of the groundwater in parts per million of calcium carbonate by mass.
Answer: If it was 3 mol of solute in 2 L of solution it would be 1.5 mol/L.
However when the solute dissolves in the water creating the solution, the volume increases. So 3 mol of solute in 2 L of water creates more than 2 L of solution.
The correct method for making a 3 mol/L solution would be to place some water into a two liter volume container. Dissolve all 3 mol of the solute into the water. Then add water to the 2 L mark. Now there is 3 mol of solute and 2 L of solution.
Explanation: I hope this helps XDDDD
Answer:
1.44 mol
Explanation:
Given data:
Mass of Cu = 46 g
Moles of Ag produced = ?
Solution:
Chemical equation:
Cu + 2AgNO₃ → 2Ag + Cu(NO₃)₂
Number of moles of Cu:
Number of moles = mass/ molar mass
Number of moles = 46 g/63.546 g/mol
Number of moles = 0.72 mol
Now we will compare the moles of Cu and silver from balance chemical equation:
Cu : Ag
1 : 2
0.72 : 2×0.72 = 1.44 mol
Thus from 46 g of Cu 1.44 moles of Ag is produced .