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2 years ago

Which equation represents neutralization?

Chemistry

1 answer:

earnstyle [38]2 years ago

6 0

Answer:

3) 2KOH(aq) + H2SO4(aq) ⇒ K2SO4(aq) + 2H2O(l)

Explanation:

KOH is a strong base and a H2SO4 is a strong acid. The two react in a neutralization reaction, producing a salt and water.

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Easy question, need help

jeka94

Answer: B= 210 amps

Explanation:

175

0.75 so you divide it so the answer it 210

since first you find for one

then you multiply 0.75 to the answer you get

Hope this helps :)

8 0

2 years ago

Read 2 more answers

"What volume of" a 0.300 M BaF2 "solution is needed to prepare" 240.0 mL of a 0.100 M F- solution

zhannawk [14.2K]

Use M x V = M' x V'

0.300 x V = 0.100 x 250

V = .......... ml

6 0

3 years ago

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

3 years ago

What is the element with period 2 group 14

Ghella [55]

Answer:

Carbon

Explanation:

7 0

3 years ago

Read 2 more answers

PLSSS HELPPPPPPPP. I will give brainliest

nasty-shy [4]

Answer:

Ionic bond

Explanation:

Covalent bonds can only form between non-metals and copper is a metal so it would be an ionic bond.

6 0

2 years ago