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motikmotik
2 years ago
8

Questions & Conclusions:

Chemistry
1 answer:
dem82 [27]2 years ago
3 0

The amount of KNO₃ precipitated out of solution when you cooled the solution from 100°C to -22°C is obtained from the solubility curve

<h3>What is a solubility curve?</h3>

A solubility curve is a curve of the solubility of a solute against temperature.

The solubility curve shows that the solubility of different solute at different temperatures.

The solubility curve of KNO₃ is as shown. Solubility at 100 °C and  -22 °C is not shown in the curve.

However, the amount of KNO₃ precipitated out of solution when cooled the solution from 100 °C to -22 °C can be determined by subtracting the amount of solute dissolve at -22 °C from that dissolved at 100 °C.

In conclusion, the solubility curve is used to determined the amount of solute dissolved in a given volume of solvent at different temperatures.

Learn more about solubility curve at: brainly.com/question/928930

#SPJ1

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How do you balance the equation Hydrogen plus Oxygen yield water?
Andre45 [30]
Hey there! Hello!

Not sure if you still need the answer to this question, but I'd love to help out if you do. 

So, the way to balance this equation is pretty simple. First, you need to keep in mind that molecules of hydrogen and oxygen do not come in single molecules, but in bonded pairs, represented by H2 and O2. 

H2+O2=H2O

But, that's incorrect. The combination of 2 hydrogen molecules with 1 oxygen molecule yields water, but that leaves one oxygen molecule leftover. When broken down, this is how many of each molecule is on each side of the previously stated equation:

Left:
H: 2
O: 2

Right:
H: 2
O: 1

So we have to multiply H2O on the right side by 2 in order to get this:

H2+O2=2(H2O)

Left: 
H: 2
O: 2

Right: 
H: 4
O: 2

The last step is to multiply H2 on the left by two to make it match up with the right side, balancing the equation:

2(H2)+O2=2(H2O)

Left: 
H: 4
O: 2

Right: 
H: 4
O: 2

That makes our equation balanced! I hope this helped you out, feel free to ask any additional questions if you need further clarification. :-)
5 0
3 years ago
What are the primary chemical components present in a phosphate buffer at ph 7.4? H3po4 and po43–?
fenix001 [56]

Answer :

The correct answer for primary component of phosphate buffer at pH = 7.4 is H₂PO₄⁻ and HPO₄²⁻ .

<u>Buffer solution :</u>

It is a solution of mixture of weak acid and its conjugate base OR weak base and its conjugate acid . It resist any change in solution when small amount of strong acid or base is added .

<u>Capacity of a good buffer : </u>

A good buffer is identified when pH = pKa .

From Hasselbalch - Henderson equation which is as follows :

pH = pka + log \frac{[A^-]}{[HA]}

If [A⁻] = [HA] ,

pH = pka + log 1

pH = pKa

This determines that if  concentration of  weak acid  and its conjugate base are changed in small quantity , the capacity of  buffer to maintain a constant pH is greatest at pka .  If the amount of [A⁻] or [HA] is changed in large amount , the log value deviates more than +/-  1M and hence pH .

Hence Buffer has best capacity at pH = pka .

<u>Phosphate Buffer : </u>

Phosphate may have three types of acid-base pairs at different pka ( shown in image ).

Since the question is asking the pH = 7.4

At pH = 7.4 , the best phosphate buffer will have pka near to 7.4 .

If image is checked the acid - base pair  " H₂PO₄⁻ and HPO₄²⁻  has pka 7.2 which is near to pH = 7.4 .

Hence we can say  , the primary chemical component of phosphate buffer at pH = 7.4  is H₂PO₄⁻ and HPO₄²⁻  .


8 0
3 years ago
This formula equation is unbalanced. BaCl2(aq) + Na2CO3(aq) mc017-1.jpg BaCO3(s) + NaCl(aq) Which coefficient should be placed i
Nookie1986 [14]
You would need to put a 2 in front of NaCl.

Hope this helps!!
~Kiwi
8 0
3 years ago
Read 2 more answers
What is glacial acetic acid? What function does it have?
solniwko [45]

Answer:

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Explanation:

6 0
2 years ago
What is the volume of an object that has Mass=100g and Density= 745g/mL. Give your answer to 4 sig figs
lilavasa [31]

Answer:

the answer is

0.1342 mL

hope that will help you ❤️

7 0
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