ABCDEF is. regular hexagon wth O at the center.ehat kind of quadrilaterals are ABCO and ACDF?

Find all the angles listed. also list all of the lines that are secants, chords and tangents

Tanzania [10]

Answer:

Secants – 1. <CBG 2. <AGF 3. <ABD

Tangent – 1. <CDE

Chords – 1. <BD 2. <DF 3. <BG 4. <BF 5. <GD 6. <FG

Angles – 1. 45 2. 75 3. 35 4. 70 5. 75 6. 55 7. 50 8. 25 9. 35 10. 70 11. 50 12. 25 13. 70 14. 50. 15. 60 16. 85 17. 95 18. 85 19. 95

Step-by-step explanation:

4 0

2 years ago

For the reaction 2Fe + O2 → 2FeO, how many grams of iron oxide are produced from 42.4 mol of iron?

Butoxors [25]

In the balanced reaction

2 Fe + O₂ → 2 FeO

2 moles of iron (Fe) react with 1 mole of molecular oxygen (O₂) to produce 2 moles of iron oxide (FeO). The ratio of Fe to FeO is 1-to-1, so if one starts with 42.4 mol of Fe, one will end up with the same amount of FeO, 42.4 mol.

Look up the molar mass of Fe and O:

• Fe = 55.845 g/mol

• O = 15.999 g/mol

Then the molar mass of FeO is approximately 71.835 g/mol, and so the mass of 42.4 mol of FeO is

(42.4 mol) × (71.835 g/mol) ≈ 3050 g

8 0

2 years ago

In ΔUVW, w = 3 inches, ∠W=23° and ∠U=73°. Find the length of u, to the nearest 10th of an inch.

kirza4 [7]

Answer:

<h2>7.4inches</h2>

Step-by-step explanation:

Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.

According to the rule;

$\frac{u}{sinU} = \frac{v}{sinV} = \frac{w}{sinW}\\\frac{u}{sinU} = \frac{w}{sinW}$

Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;

$\frac{u}{sin73^{0} } = \frac{3}{sin23^{0} }\\usin23^{0} = 3sin73^{0}\\u = \frac{3sin73^{0} }{sin23^{0} }\\u = \frac{2.87}{0.39} \\u = 7.358\\u = 7.4in$

The length of u is 7.4inches to nearest 10th of an inch

6 0

3 years ago

in year 4 the store sold 112% of the total number of scooters sold during the previous three years combined determine the number

Margarita [4]

Answer:

2, 240

Step-by-step explanation:

In the table, the values should be

Year 1 725

Year 2 579

Year 3 696

Since Year 4 sold 112% of the previous 3 years combined, we add 725+579+696=2000. We can find 112% by writing a proportion.

$\frac{112}{100} =\frac{x}{2000}$

We solve through cross multiplication of numerator and denominator of the opposite fraction.

$112(2000)=100(x)\\224000=100x\\2,240=x$

3 0

3 years ago

Read 2 more answers

A truck loaded with 8000 electronic circuit boards has just pulled into a firm’s receiving dock. The supplier claims that no mor

Juliette [100K]

Answer:

The 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

Let X = number of boards that fall outside the most rigid level of industry performance specifications.

In a random sample of 300 boards the number of defective boards was 12.

Compute the sample proportion of defective boards as follows:

$\hat p =\frac{12}{300}=0.04$

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The critical value of z for 95% confidence level is,

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

3 0

3 years ago

ABCDEF is. regular hexagon wth O at the center.ehat kind of quadrilaterals are ABCO and ACDF?​

ABCDEF is. regular hexagon wth O at the center.ehat kind of quadrilaterals are ABCO and ACDF?