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mario62 [17]
3 years ago
8

ABCDEF is. regular hexagon wth O at the center.ehat kind of quadrilaterals are ABCO and ACDF?​

Mathematics
1 answer:
Kruka [31]3 years ago
4 0

Answer:

Step-by-step explanation:

Is there a picture maybe?

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Dvinal [7]
1.They basically all did one big bug,not separate hugs with different bears.
3 0
2 years ago
Heelp will give brianliest
gizmo_the_mogwai [7]

Answer:

256

Step-by-step explanation:

4(7)^2 + 30(2)

196 + 60 = 256

4 0
3 years ago
The width of a rectangle is 3.4 feet. The perimeter is 12.6 feet what is the length
lesya692 [45]

Answer:

the answer is 2.90

Step-by-step explanation:

Picture a rectangle, if one side is 3.4 then the other side 3.4. Add those two togerther gives you 6.8. Now you can subtract 6.8 from the perimeter which is 12.6 then that gives you 5.8. Then you split the 5.8 which give you 2.90 which is the length of the rectangle. So if you label all the sides of the rectangle like this 3.4 + 3.4 + 2.90 + 2.90 = 12.6

7 0
3 years ago
The domain of y = cos x is _______.
Lana71 [14]

ANSWER

d. The set of all real numbers

EXPLANATION

The basic cosine function ,

y =  \cos(x)

is continuous everywhere.

The function is defined for all real values of x.

The domain is the set all values of x that will make the function defined.

The domain is all real numbers.

The correct choice is D.

6 0
3 years ago
Historical data for a local manufacturing company show that the average number of defects per product produced is 2. In addition
charle [14.2K]

Answer:

The probability that there will be a total of 7 defects on four units  is 0.14.

Step-by-step explanation:

A Poisson distribution describes the probability distribution of number of success in a specified time interval.

The probability distribution function for a Poisson distribution is:

P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}, x=0,1,2,3,...

Let <em>X</em> = number of defects in a unit produced.

It is provided that there are, on average, 2 defects per unit produced.

Then in 4 units the number of defects is, (2\times4)=8.

Compute the probability of exactly 7 defects in 4 units as follows:

P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}\\P(X=7)=\frac{e^{-8}8^{7}}{7!}\\=\frac{0.0003355\times2097152}{5040}\\ =0.1396\\\approx0.14

Thus, the probability of exactly 7 defects in 4 units is 0.14.

8 0
3 years ago
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