The independent variable would be the dry ice being placed in the water/other liquid (D) and the dependent variable would be the water/other liquid the dry ice (ID) is being placed in.
It's d, here's why.
Stoichiometry: N2 + H2 (for instance) --> NH3
There are 2 Nitrogen atoms (or parts) of Nitrogen on the left side of the equation, and 2 Hydrogen, and only one Nitrogen but three Hydrogen on the other side. Where did the extra Nitrogen go? Where did that Hydrogen come from? The answer is Stoichiometry.
N2 + H2 --> NH3 has to be balanced, so we add coefficients to the reactants and products, which indicate in what ratio they are consumed in the reaction. They effectively multiply the subscripts on the elements.
To balance Nitrogen, we have to add a 2 to the front of NH3, so we get 2NH3. Nitrogen is balanced, but Hydrogen isn't. There are now 6 Hydrogen being produced by the reaction, so we can add a 3 to the products side, making 3H2.
Now we have N2 + 3H2 --> 2NH3, and everything is balanced.
“Many of the objections are long standing but apparently unknown to many geophysicists, while some are peculiar to the new global tectonics. The conclusions drawn, in order of probability, are (1) the continents have almost certainly not moved with respect to each other; (2) convection is not active throughout the whole mantle; (3) even if convection is active in the upper mantle it cannot account for drift; (4) pole positions derived from paleomagnetism, and results of this method of investigation in its global form generally, are afflicted with an unknown cause of error and are in any case too inexact for drift reconstructions.”
(Wesson, 1972)
Answer:
B
Explanation:
because a periodic table shows the arrangement of element according to their atomic number and their valence neither
isotopes nor colour
Answer:
Explanation:
CH₃OH + CO = CH₃COOH .
32 g 28 g 60 g
CH₃OH = 15 g ; CO = 10 g
32 g of CH₃OH reacts with 28 g of CO
15 g of CH₃OH reacts with 28 x 15 / 32 g of CO
= 13.125 g of CO .
CO given = 10 g , so CO is the limiting reagent .
28 g of CO reacts with CH₃OH to produce 60 g of CH₃COOH
10 g of CO reacts with CH₃OH to produce 60 x 10 / 28 g of CH₃COOH
CH₃COOH produced = 600 / 28 g = 21.42 g .