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otez555 [7]
2 years ago
5

This table lists some characteristics of two planets. Which statement is true?

Chemistry
2 answers:
LekaFEV [45]2 years ago
5 0

gravity

Explanation:

gravity is the same in any planet

Sav [38]2 years ago
3 0

Answer:

40 N

Explanation:

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If 15.6 grams of copper (ii) chloride react with 20.2 grams of sodium nitrate how many grams of sodium chloride can be formed? W
olasank [31]

Answer:

- 13.56 g of sodium chloride are theoretically yielded.

- Limiting reactant is copper (II) chloride and excess reactant is sodium nitrate.

- 0.50 g of sodium nitrate remain when the reaction stops.

- 92.9 % is the percent yield.

Explanation:

Hello!

In this case, according to the question, it is possible to set up the following chemical reaction:

CuCl_2+2NaNO_3\rightarrow 2NaCl+Cu(NO_3)_2

Thus, we can first identify the limiting reactant by computing the yielded mass of sodium chloride, NaCl, by each reactant via stoichiometry:

m_{NaCl}^{by\ CuCl_2}=15.6gCuCl_2*\frac{1molCuCl_2}{134.45gCuCl_2} *\frac{2molNaCl}{1molCuCl_2} *\frac{58.44gNaCl}{1molNaCl} =13.56gNaCl\\\\m_{NaCl}^{by\ NaNO_3}=20.2gNaNO_3*\frac{1molNaNO_3}{84.99gNaNO_3} *\frac{2molNaCl}{2molNaNO_3} *\frac{58.44gNaCl}{1molNaCl} =13.89gNaCl

Thus, we infer that copper (II) chloride is the limiting reactant as it yields the fewest grams of sodium chloride product. Moreover the formed grams of this product are 13.56 g. Then, we take 13.56 g of sodium chloride to compute the consumed mass sodium nitrate as it is in excess:

m_{NaNO_3}^{by\ NaCl}=13.56gNaCl*\frac{1molNaCl}{58.44gNaCl}*\frac{2molNaNO_3}{2molNaCl} *\frac{84.99gNaNO_3}{1molNaNO_3}=19.72gNaNO_3

Therefore, the leftover of sodium nitrate is:

m_{NaNO_3}^{leftover}=20.2g-19.7g=0.5gNaNO_3

Finally, the percent yield is computed via:

Y=\frac{12.6g}{13.56g} *100\%\\\\Y=92.9\%

Best regards!

6 0
2 years ago
Write the balanced equation of aluminium + copper chloride and ammonium chloride + copper ​
Scorpion4ik [409]

Answer:

2Al+3CuCl2=>3Cu + 2AlCl3

NH4Cl catalyses the oxidation of Cu

6 0
3 years ago
When concentrated sulfuric acid is poured onto sugar in a beaker and stirred, a vigorous exothermic reaction eventually occurs.
Vlada [557]
Missing question:
I. switching from granulated sugar to pow-dered sugar.
II. switching from powdered sugar to gran-ulated sugar.
III. warming up the sulfuric acid.
IV. putting the sulfuric acid container in an ice bath before use.
1. IV only
2. II only
3. III only
4. I and IV
5. I and III.
6. I only.
7. II and III
<span>8. II and IV.
Answer is: 5. </span>I and III.
If the surface area and temperature are increased, speed of reaction also increased<span>.</span>
7 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
Iteru [2.4K]

Answer:

The mass of the products left in the test tube will be less than that of the original reactants.

Explanation

The equation for the reaction is

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

 1.0          3.0              3.9             0.1

Assume you started with 1.0 g of Mg.

It will react with 3.0 g of HCl to form 3.9 g of MgCl2 and 0.1 g of H2

.

Mass of reactants = mass of products

        1.0 g + 3.0 g = 3.9 g + 0.1 g

                    4.0 g = 4.0 g

The Law of Conservation of Mass is obeyed.

However, your test tube and its contents will weigh 0.1 g less than it did before the reaction.

Does that contradict the Law of Conservation of Mass? It does not.

One of the products was the gas, hydrogen, and it escaped from the test tube. You weren't measuring all the products, so test tube and its contents weighed less than before.

7 0
3 years ago
What is fulcrum? This is for science middle school.
I am Lyosha [343]

Answer: where a lever rests or is supported and where it pivots

Explanation:

3 0
3 years ago
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