Answer:
Explanation:
in a combustion of ethane 2 moles of ethane react with 7 moles of O2
now no of moles in 54 gram of O2=mass/ molar mass
moles =54/32=1.7 moles
if 7 moles of O2 required 2 moles of ethane then 1.7 mole required=?
7 moles of O2=2 moles of C2H6
1.7 moles of O2=1.7*2/7=0.5 moles of C2H6
0.5 moles of C2H6 contain how much grams=?
mass= moles*molar mass=0.5*30=15
Answer:
3 salad = 3 lettuce + 6 tomatoes + 9 three carrots
Coefficients: 3, 6, 9
Explanation:
1 salad = 1 lettuce + 2 tomatoes + 3 three carrots
<em>Multiply all the coefficients of 1 salad by 3:</em>
3(1 salad) = 3(1 lettuce + 2 tomatoes + 3 three carrots)
<em>Expand the equation:</em>
3 salad = 3 lettuce + 6 tomatoes + 9 three carrots
The magnitude of the orbital angular momentum of the electron is doubled when the radius of the electron orbit increases by a factor of four.
<h3>
What is orbital angular momentum?</h3>
The orbital angular momentum is the sum of angular momenta of all electrons, it is the rotational analog of the linear momentum.
The formula of angular momentum
Thus, the magnitude of the orbital angular momentum of the electron is doubled when the radius of the electron orbit increases by a factor of four.
Learn more about orbital angular momentum
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Chemical reaction: PCl₅ → PCl₃ + Cl₂.
n(PCl₅) = 0,366 mol.
V(PCl₅) = 4,45 L.
c(PCl₅) = n(PCl₅) ÷ V(PCl₅).
c(PCl₅) = 0,366 mol ÷ 4,45 L.
c(PCl₅) = 0,082 mol/L.
Kc = 1,80.
[PCl₃] = [Cl₂] = x.
Kc = [PCl₃] · [Cl₂] ÷ [PCl₅].
1,80 = x² ÷ (0,082 mol/L - x).
Solve quadratic eqaution: x = [PCl₃] = 0,078 mol/L.
[PCl₅] = 0,082 mol/L - 0,078 mol/L.
[PCl₅] = 0,004 mol/L.
False, 0 degrees on the K scale is absolute zero.
