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4 years ago

What is the correct order for the development of the atomic model

Chemistry

1 answer:

tensa zangetsu [6.8K]4 years ago

3 0

Answer: I think it's A. C-A-D-B

Explanation:

John Dalton's theory was publicized in 1803

J.J Thomson's theory was publicized in 1904

Ernest Rutherford's theory was publicized in 1911

And Neil Bohr's was publicized in 1926

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How many moles are equal to 6.02 x 10^23 atoms of mg

spayn [35]

Answer: 1

Explanation:

a mole is always equal to 6.02 x 10^23 molecules, or in this case, atoms

so to find the number of moles, divide total atoms / 6.02 x 10^23

total atoms = 6.02 x 10^23

6.02 x 10^23 / 6.02 x 10^23 = 1

so 1 mole

6 0

4 years ago

No. free poijnts ,,,,,,,

arsen [322]

Yes free pointssssss

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3 years ago

Read 2 more answers

A 1.0 L sample of an aqueous solution contains 0.10 mol of NaCl and 0.10 mol of CaCl2. What is the minimum number of moles of Ag

Annette [7]

Answer:

The answer to your question is: 0.3 moles of AgNO₃

Explanation:

1.0 L sample

0.1 mol of NaCl

0.1 mol of CaCl₂

AgNO₃ = ? moles

Reactions

NaCl + AgNO₃ ⇒ AgCl + NaNO₃

Then 1 NaCl mol --------------- 1 AgNO₃

0.1 mol -------------- x

x = 0.1 moles of AgNO₃ needed

CaCl₂ + 2 AgNO₃ ⇒ 2 AgCl + Ca(NO₃)₂

Then 1 mol of CaCl₂ ------------- 2 moles of AgNO₃

0.1 mol ------------- x

x = 0.2 moles of AgNO₃

Total moles of AgNO₃ = 0.1 + 0.2 = 0.3

5 0

3 years ago

Why are there airlock on Mars and how do you think they work

UkoKoshka [18]

Answer:

to protect astronauts from dieing from no air or presurre

Explanation:

3 0

3 years ago

An alternative definition of electronegativity is Electronegativity= constant (I.E — E.A.) where I.E. is the ionization energy a

Kazeer [188]

Answer:

The electronengativity values of given elements is as follows.

Fluorine - 4

Chlorine -3

Bromine - 2.9

Iodine- 2.5

Explanation:

Electronegativity =consant (I.E-E.A)

The electron affinity and ionization energy values of the given elements is as follows.

(In attachment)

First we have to find the value of constant by using the fluorine atom to whom the electronengativity taken as "4".

Fluorine:

$4=constant[1678-(-327.8)]$

$Constant=0.0019942168$

By using this constant values we can find electronegatvity values of remaining elements.

Chlorine:

$Electronegativity=0.0019942168[1255+348.7]=3.1980\sim 3$

Therefore, electronegativity of chlorine is 3.

Bromine:

$Electronegativity=0.0019942168[1138+324.5]=2.91\sim 2.9$

Therefore, electronegativity of bromine is 2.9.

Iodine:

$Electronegativity=0.0019942168[1007+295.7]=2.59\sim 2.5$

Therefore, electronegativity of iodine is 2.5.

8 0

3 years ago