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4 years ago

What is the correct order for the development of the atomic model

Chemistry

1 answer:

tensa zangetsu [6.8K]4 years ago

3 0

Answer: I think it's A. C-A-D-B

Explanation:

John Dalton's theory was publicized in 1803

J.J Thomson's theory was publicized in 1904

Ernest Rutherford's theory was publicized in 1911

And Neil Bohr's was publicized in 1926

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What is oxidized in the following reaction? Na+CI —>NaCI

serious [3.7K]

Answer:

the reducing agent is the Na ion, therefore the Na ion is oxidised. The oxidising agent is Cl ion, therefore the Cl ion is reduced.

5 0

2 years ago

How much heat is required to raise the temperature of 10.35g of CCl4 from 32.1°c to 56.4°c

Travka [436]

We are going to use this formula:

Q = M*C*ΔT

when Q is the heat required

M is the mass of CCl4 = 10.35 g

C is the specific heat capacity of CCl4 = 0.874J/g.c

and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C

∴ Q = 10.35g * 0.874 * 24.3 °C

= 219.8 J

4 0

4 years ago

Calculate the percent activity of the radioactive isotope iodine-131 remaining after 3 half-lives.

vovangra [49]

Half life of a radio-active material is refereed to the time required for reducing its activity to 50 %.

Now, when I-131 passes 1st half life, it's activity will reduce to half i.e. 50%

When, I-131 passes 2nd half life, activity of I-131 will be reduced to 25%

On passing, 3rd half-life, percent activity of the I-131 remaining will be 12.5 %.

3 0

4 years ago

A 2 kg toy car and a 5 kg toy car are pushed with an equal amount of force. Which toy car will have the least acceleration?

pishuonlain [190]

Answer:

The 5 kg toy car will have least acceleration

Explanation:

3 0

3 years ago

How many liters of oxygen are required to completely react with 2.0 liters of CH4 at30 °C and 3.0 atm?CH4(g) + 2O2(g) → CO2(g) +

Dominik [7]

1) Write the chemical equation.

$CH_4+2O_2\rightarrow CO_2+2H_2O$

2) List the known and unknown quantities.

Sample: CH4.

Volume: 2.0 L.

Temperature: 30 ºC = 303.15 K.

Pressure: 3.0 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

Moles: unknown.

3) Moles of CH4.

3.1- Set the equation.

$PV=nRT$

3.2- Plug in the known values and solve for n (moles).

$(3.0\text{ }atm)(2.0\text{ }L)=n*(0.082057\text{ }L*atm*K^{-1}mol^{-1})(303.15\text{ }K)$ $n=\frac{(3.0\text{ }atm)(2.0\text{ }L)}{(0.082057\text{ }L*atm*K^{-1}*mol^{-1})}=$ $n=0.24\text{ }mol\text{ }CH_4$

4) Moles of oxygen that reacted.

The molar ratio between CH4 and O2 is 1 mol CH4: 2 mol O2.

$mol\text{ }O_2=0.24\text{ }CH_4*\frac{2\text{ }mol\text{ }O_2}{1\text{ }mol\text{ }CH_4}=0.48\text{ }mol\text{ }O_2$

5) Volume of oxygen required.

Sample: O2.

Moles: 0.48 mol.

Temperature: 30 ºC = 303.15 K.

Pressure: 3.0 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

Volume: unknown.

5.1- Set the equation.

$PV=nRT$

5.2- Plug in the known values and solve for V (liters).

$(3.0\text{ }atm)(V)=0.48\text{ }O_2*(0.082057\text{ }L*atm*K^{-1}mol^{-1})(303.15\text{ }K)$ $V=\frac{(0.48\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(303.15\text{ }K)}{3.0\text{ }atm}$ $V=3.98\text{ }L$

3.98 L of O2 is required to react with 2.0 L CH4.

6 0

2 years ago