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ddd [48]
3 years ago
13

Identify the limiting reactant in the reaction of iron and chlorine to form FeCl3, if 24.5 g of Fe and 37.9 g of Cl2 are combine

d. Determine the amount (in grams) of excess reactant that remains after the reaction is complete.
Chemistry
1 answer:
stellarik [79]3 years ago
7 0

Answer:

asasasas sa yes the chgemistry si fgoodfsdyes e

Explanation:

yse good svbchameriee

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The electron configuration for an element in the halogen group should always end with Question 16 options:
ludmilkaskok [199]

Answer:

ns²np⁵

Explanation:

The electronic configuration of elements of halogen group ends with 7 electrons in its outer most shell and they distributed as ns²np⁵.

Such as Cl (17 electron): 2,8,7 which is 1s²2s²2p⁶3s²3p⁵.

5 0
3 years ago
MORE THEN ONE ANSWER Factors affecting energy transfer
abruzzese [7]

Answer:

Sorry I'm not sure about this one. It might be The first one or the third one

7 0
3 years ago
Read 2 more answers
A chemist prepares a solution by adding 258 mg of K2Cr2O7 (MW = 294.19 g/mol ) to a volumetric flask, and then adding water unti
Maksim231197 [3]

Answer: Molarity of the prepared solution is 1.75\times 10^{-3}mole/L

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

V_s = volume of solution in ml = 500 ml

moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{0.258g}{294.19g/mol}=8.77\times 10^{-4}mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{8.77\times 10^{-4}moles\times 1000}{500ml}=1.75\times 10^{-3}mole/L

Thus molarity of the prepared solution is 1.75\times 10^{-3}mole/L

3 0
3 years ago
An object that allows almost all that light that strikes it to pass through and that forms a clear image is
ra1l [238]

Answer: the object is transparent.

Explanation:

let me know if this helps

5 0
3 years ago
O
viva [34]

Answer:

The second and third option are isotopes of Bromine

Z=  35 A = 79

A = 79  N= 44

Explanation:

Step 1: What are isotopes ?

⇒ Elements  with same atomic number (Z) ( this means the same number of electrons and protons) but a different number of neutrons (N)

The atomic number (visible on the periodic table) is the number of protons.

The atomic mass is  the sum of the protons (Z) and neutrons (N), and is showed as 'A'. So A = Z+N

If we look at the periodic table, we can see that the atomic number of bromine (Z) = 35. This means the amount of protons = 35. Since isotopes have the same amount of protons, all isotopes of bromine, have 35 protons.

1) Z = 79, A = 196

Z = protons = electrons .So this element has 79 protons, as well as 79 electrons.

196 = 79 + N ⇒ N = 196 - 79 = 117 neutrons

⇒Since it doesn't have 35 protons, it isn't an isotope of Bromine, but of Gold (Au): 196Au

2) Z = 35 , A = 79

Z = protons = electrons .So this element has 35 protons, as well as 35 electrons.

79 =35 + N ⇒ N = 79 - 35= 44 neutrons

⇒Since it does have 35 protons, it is an isotope of Bromine. This isotope has 44 neutrons

⇒ This is 79Br, which is a stable isotope of Bromine.

3) A=79, N = 44

Z = A - N ⇒ Z = 79 - 44 = 35

Z = protons = electrons .So this element has 35 protons, as well as 35 electrons. It also has 44 neutrons.

⇒Since it does have 35 protons, it is an isotope of Bromine, with 44 neutrons: 79Br

4) Z = 44, N = 44

Z = protons = electrons .So this element has 44 protons, as well as 44 electrons.

A = 44 + 44 ⇒ A = 88  

⇒Since it doesn't have 35 protons, it isn't an isotope of Bromine, but of Ruthenium (Ru) : 88Ru

⇔So the <u>second</u> and<u> third</u> option are isotopes of Bromine

6 0
3 years ago
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