For 12 divided by 587, I got 0.02044293.
For 587 divided by 12, I got 48.9166666666666.
I hope this helps.
Find a 92.9% confidence interval for the difference p1−p2p1−p2 of the population proportions.
Hint: For a level of confidence (1−α)⋅100%(1−α)⋅100%, z∗z∗ is the value that leaves an area of (1−α)/2(1−α)/2 to its right in a standard normal distribution
I hope that helps
1018262910101101 explanation:
Multiply 5 by 6 and get 30 for you answer. 30 will be the area. Its that simple :)
D 120 sq in is the answer
