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balandron [24]
3 years ago
13

Function 1: Sam is 150 feet below sea level in a cave and trying to climb back out to safety at zero elevation. He climbs at a r

ate of 4 feet per
minute. This situation can be modeled with a function where C(m) represents the number of feet he has left to climb in order to reach
zer elevation
Function 2: The function below shows the number of feet that Sam's friend, Arthur, has left to climb
to reach zero elevation from a different cave as a function of time x in minutes). Assume that the domain is represented by all real numbers for
0 < 30
X
f(x)
5
-125
10
-100
15
-75
20
-50
25
-25
30
0
Who climbs at a faster rate? Make sure to explain your answer and how you know
Mathematics
2 answers:
prisoha [69]3 years ago
7 0

Answer:

Start at -150, then add 3(-5), then add 122.2. -150 + 3(-5) + 122.2 = -45.3.

Naddika [18.5K]3 years ago
5 0

The answer is -45.3 feet depth. while minus sign shows the descend under the water with water surface as starting point.

Step-by-step explanation:

Initial depth of diver under the water =-150feet=−150feet

Diver descends 5 feet per minute for 3.5 minutes =3.5*(-5)=3.5∗(−5)

                                                                                =-17.5=−17.5

Note: minus sign shows that the diver is under the water.

Diver ascends =122.2feet=122.2feet

Now adding all the terms a below as a numerical expression.

Current Depth of Diver after he descends 5 feet for 3.5 minutes and ascend 122.2 feet after  =-150-17.5+122.2=−150−17.5+122.2

                           =45.3feet=45.3feet

By taking the initial depth of diver from which we add or subtract the changes made when he ascends or descends in the water to get the current depth.

PLEASE MARK ME AS BRAINLIEST

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