Hey who can solve this

Carina begins to solve the equation -4 - 2/3x = -6 by adding 4 to both sides. Which statements regarding the rest of the solving

Andru [333]

Answer:

A.) After adding 4 to both sides, the equation is $-\frac{2}{3}x=-2$

C.) The equation can be solved for x using exactly one more step by multiplying both sides by $-\frac{3}{2}$

D.) The equation can be solved for x using exactly one more step by dividing both sides by $-\frac{2}{3}$

Step-by-step explanation:

The correct questions is as follows:

Carina begins to solve the equation -4-2/3x=-6 by adding 4 to both sides. Which statements regarding the rest of the solving process could be true? Check all that apply.

A.) After adding 4 to both sides, the equation is -2/3x=-2.

B.) After adding 4 to both sides, the equation is -2/3x=-10 .

C.) The equation can be solved for x using exactly one more step by multiplying both sides by -3/2.

D.) The equation can be solved for x using exactly one more step by dividing both sides by -2/3.

E.) The equation can be solved for x using exactly one more step by multiplying both sides by -2/3.

Given equation:

$-4-\frac{2}{3}x=-6$

To show the steps we will carry out in order to solve for $x$

Solution:

Solving for $x$

Step 1:

Adding both sides by 4

$4-4-\frac{2}{3}x=-6+4$

Thus, we get:

$-\frac{2}{3}x=-2$

Thus statement A is correct.

Step 2:

Multiplying both sides by $-\frac{3}{2}$

$-\frac{3}{2}\times -\frac{2}{3}x=-2\times -\frac{3}{2}$

Thus, we get:

$x=3$ [Two negatives multiply to give a positive]

This proves that statement C is correct.

Or Step 2:

Dividing both sides by $-\frac{2}{3}$

$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{-2}{-\frac{2}{3}}$

Thus, we get:

$x=-2\times -\frac{3}{2}$ [On dividing with a fractional divisor, we take reciprocal and multiply it with the dividend.]

$x=3$ [Two negatives multiply to give a positive]

This prove that statement D is correct.

5 0

2 years ago

The cover of a soccer ball consists of interlocking regular pentagons and regular hexagons. Why can't they be interlocked in thi

FinnZ [79.3K]

Answer: Because of gaps between the vertex of Pentagons and hexagon.

Step-by-step explanation:

The Pentagon has 5 sides and 5 vertex angles. While hexagon has 6 sides and six vertex angles

The sum of the angle of polygon is equal to ( n - 2 )180

Sum of the angle of a Pentagon will be: (5 - 2)×180 = 540

Each vertex angle of a Pentagon = 540/5 = 108

Sum of the angle of hexagon will be: (6 - 2)×180 = 720

Each vertex angle of a hexagon =

720/6 = 120

To interlock Pentagon and hexagon, the sum of the combination of vertex angles of both must be equal to 360 ( sum of the angles at a point = 360)

Since there is no number of combinations that can be equal to 360, there will surely be a gap.

5 0

2 years ago

The perimeter of square JKLM is 48 units.

Mashcka [7]

Perimeter = 4 x sides
48 = 4 (x + 3)
48 = 4x + 12
36 = 4x
x = 9

Check:
x + 3 = 9 + 3 = 12
12 x 4 = 48

4 0

1 year ago

Read 2 more answers

Need helpppppppppp! Show work plz

Natasha_Volkova [10]

Answer:

9/169

Step-by-step explanation:

JQK of 4 suits = 12 cards

12/52x12/52=

3/13x3/13=

9/169

5 0

2 years ago

6% sales tax, hotel charges $265 find cost before tax?

Mama L [17]

265 x 0.06 = 15.9

265 - 15.9 = 249.1

249.1 is your answer

hope this helps

3 0

3 years ago

Read 2 more answers