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adelina 88 [10]
3 years ago
13

Find the volume of the figure. Round to the nearest hundredth.

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0

Answer:

Volume=2521.91 mm³

Step-by-step explanation:

d=13, r=13/2=6.5, h=19

volume=πr²h

=π(6.5)²×19

=<u>2521.91 mm³</u>

<u>hope it helps</u>

<u>have a great day!!</u>

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Answer:

(t,s)

Step-by-step explanation:

this point has the x value t and the y value s that is missing.

4 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

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Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
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Answer:
300
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Step-by-step solution

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Answer:

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Step-by-step explanation: put the whole #and make it into a fraction like this e.g.

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