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3 years ago

What is the volume of the prism?

Mathematics

1 answer:

Triss [41]3 years ago

4 0

Answer:

volume of hexagonal prism = area of base * perpendicular height

Step-by-step explanation:

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Solve this convert th following numbers in base 10 to numbers in base five

artcher [175]

Answer:

123

304

314

Step-by-step explanation:

38, 79, 84 in base 10 to base 5

5 __ 38

5 __7 r 3

5 __1 r 2

___0 r 1

From bottom to top

38 base 10 = 123 base 5

2.)

5 __ 79

5 __15 r 4

5 __3 r 0

___0 r 3

From bottom to top

38 base 10 = 304 base 5

3.)

5 __ 84

5 __16 r 4

5 __ 3 r 1

____ 0 r 3

From bottom to top

38 base 10 = 314 base 5

5 0

3 years ago

Somebody please help me please i help asap!!!!

ruslelena [56]

1) the slope for the points (-4,7) and (-7,-15) is -2.

2) The slope for the function b is D) 2/11

Hope this helps!

5 0

3 years ago

Read 2 more answers

State whether the y-values are increasing ,decreasing,or neither as x increases for problem y=1.5x

mash [69]

The y-values are increasing, as x increases in this problem.

6 0

3 years ago

What is the value of F(x) = 4x+9 When x= 5

Elodia [21]

Answer:

f(5) = 29

Step-by-step explanation:

Step 1: Identify the function

f(x) = 4x + 9

Step 2: Let x equal 5 in the function

f(5) = 4(5) + 9

Step 3: Multiply

f(5) = 20 + 9

Step 4: Add

f(5) = 29

Answer: 29

8 0

4 years ago

Read 2 more answers

1. Quadrilateral ABCD has vertices A(-1, 1), B(2, 3), C(6, 0) and D(3, -2). Determine using coordinate geometry whether or not t

deff fn [24]

Answer:

The Conclusion is

Diagonals AC and BD,

a. Bisect each other

b. Not Congruent

c. Not Perpendicular

Step-by-step explanation:

Given:

[]ABCD is Quadrilateral having Vertices as

A(-1, 1),

B(2, 3),

C(6, 0) and

D(3, -2).

So the Diagonal are AC and BD

To Check

The diagonals AC and BD

a. Bisect each other. B. Are congruent. C. Are perpendicular.

Solution:

For a. Bisect each other

We will use Mid Point Formula,

If The mid point of diagonals AC and BD are Same Then

Diagonal, Bisect each other,

For mid point of AC

$Mid\ point(AC)=(\dfrac{x_{1}+x_{2} }{2},\dfrac{y_{1}+y_{2} }{2})$

Substituting the coordinates of A and C we get

$Mid\ point(AC)=(\dfrac{-1+6}{2},\dfrac{1+0}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Similarly, For mid point of BD

Substituting the coordinates of B and D we get

$Mid\ point(BD)=(\dfrac{2+3}{2},\dfrac{3-2}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Therefore The Mid point of diagonals AC and BD are Same

Hence Diagonals,

a. Bisect each other

B. Are congruent

For Diagonals to be Congruent We use Distance Formula

For Diagonal AC

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A and C we get

$l(AC) = \sqrt{((6-(-1))^{2}+(0-1)^{2} )}=\sqrt{(49+1)}=\sqrt{50}$

Similarly ,For Diagonal BD

Substituting Band D we get

$l(BD) = \sqrt{((3-2))^{2}+(-2-3)^{2} )}=\sqrt{(1+25)}=\sqrt{26}$

Therefore Diagonals Not Congruent

For C. Are perpendicular.

For Diagonals to be perpendicular we need to have the Product of slopes must be - 1

For Slope we have

$Slope(AC)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Substituting A and C we get

$Slope(AC)=\dfrac{0-1}{6--1}\\\\Slope(AC)=\dfrac{-1}{7}$

Similarly, for BD we have

$Slope(BD)=\dfrac{-2-3}{3-2}\\\\Slope(BD)=\dfrac{-5}{1}$

The Product of slope is not -1

Hence Diagonals are Not Perpendicular.

6 0

4 years ago