Ask question

Ask question

All categories

schepotkina [342]

3 years ago

10

Ryan goes the mall with his friends after school. At the mall he purchases four pairs of basketball shorts and a pair of sneaker

s for $100 if he spends a total of $200 how much money did he spend on each pair of basketball shorts?

2 answers:

aleksandrvk [35]3 years ago

6 0

Given
Base ball shorts = 4
Sneakers = $100
Total = 200

Total - Sneakers
200 - 100 = 100

We have 100 left and 4 pairs of basketball shorts

Left divided by Basket ball shorts
100 divided by 4

= 25

Therefore each pair of basketball shorts costs $25

- I hope this helped and you could give me brainlest

Korvikt [17]3 years ago

4 0

Answer:

$25.00

Step-by-step explanation:

200-100=100

100/4=25

You might be interested in

How should this model be completed to represent 605 ÷ 18?

rosijanka [135]

Answer:

Check the attached image

4 0

2 years ago

How many 1/2 inch cubes can fit in a rectangular prisim with length of 2 height of 3/2 and width of 1.

Mrac [35]

Answer:

$X=6$

Step-by-step explanation:

From the question we are told that

Length $l=2$

Height $h=3/2$

Width $w=1$

Generally the equation for Volume of the Rectangular prism is mathematically given by

$v=l*h*w$

$v=2*\frac{3}{2}*1$

$v=3m^3$

Therefore the number of half 1/2 inch cube X in v is

$X=\frac{v}{1/2}$

$X=6$

3 0

3 years ago

Which fraction is equal to 12%

allochka39001 [22]

Answer:

3/25

Step-by-step explanation:

Simplify the fraction by using common factors of numerator and denominator. Now, 12% can be written as 12/100.

4 0

3 years ago

Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

7 0

3 years ago

Plz help LOL <br> 5(x-3)-x=

V125BC [204]

5(x-3)-x =
Multiply Everything In The Parentheses By 5
5x-15-x

3 0

3 years ago

Read 2 more answers